Reaction rates — OCR A-Level Chemistry
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Reaction rates explained
Reaction rates covers 15 specification points, including Simple collision theory and (a) the effect of concentration, including the….
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Open a point below for its explanation and revision guidance.
Simple collision theory
Simple collision theory explains why reaction rates vary. Particles react only when they collide with at least the activation energy and with correct orientation. Most collisions are unsuccessful because the particles lack sufficient energy. Raising concentration or pressure increases the number of particles per unit volume, so collisions become more frequent and the rate rises. Raising temperature increases both collision frequency and the proportion of particles with energy at or above the activation energy, so the effect is usually larger. A catalyst provides an alternative route with lower activation energy. The theory links the observable rate to the frequency of successful collisions.
(a) the effect of concentration, including the pressure of gases, on the rate of a reaction, in terms of frequency of collisions
Increasing the concentration of a reactant in solution, or the pressure of a gaseous reactant, packs more particles into a given volume. With more particles per unit volume, collisions between reactant particles happen more often, so the frequency of successful collisions rises and the rate of reaction increases. For gases, raising pressure compresses the same amount of gas into a smaller volume, giving an equivalent increase in particle concentration. The key link is always between concentration or pressure and collision frequency, not activation energy, which is unchanged. Rate therefore increases with concentration or pressure provided other factors stay constant.
(b) calculation of reaction rate from the gradients of graphs measuring how a physical quantity changes with time
Reaction rate is found from the gradient of a graph of a physical quantity against time. The quantity may be concentration, mass, gas volume or absorbance; the method is the same. Draw a tangent to the curve at the chosen time, then divide the change in the quantity by the change in time: rate = Δy/Δt. The gradient's sign shows whether the quantity rises or falls, so a decreasing concentration gives a negative gradient; the rate of reaction is the magnitude, so report the positive value. Units come from the axes, for example mol dm⁻³ s⁻¹ for concentration against time, or cm³ s⁻¹ for gas volume against time. At the start the tangent is steepest, so the initial rate is greatest; as reactants are used up the curve flattens and the rate falls. Choose two widely separated points on the tangent to reduce reading error.
Catalysts
A catalyst increases the rate of a reaction by providing an alternative reaction pathway of lower activation energy. It is not used up overall and is regenerated, so a small amount can catalyse a large amount of reaction. Because the activation energy is lower, a greater proportion of collisions has energy at or above the activation energy, so more frequent successful collisions occur and the rate rises. A catalyst does not change the position of equilibrium or the enthalpy change of the reaction; it only speeds the approach to equilibrium, helping both forward and reverse reactions equally. A homogeneous catalyst is in the same phase as the reactants, for example aqueous acid; a heterogeneous catalyst is in a different phase, usually a solid with gaseous or liquid reactants, and works by adsorption onto its surface.
(c) explanation of the role of a catalyst:
A catalyst provides an alternative reaction pathway of lower activation energy, so a greater proportion of collisions between particles have at least the activation energy and the rate of reaction increases. The catalyst is not consumed by the overall reaction: it takes part in one step and is regenerated in a later step, so its mass and chemical identity are restored at the end. For example, a solid catalyst adsorbs reactant molecules, weakens their bonds and holds them in a favourable orientation, then releases the products and is left unchanged. The catalyst does not change the position of equilibrium or the overall enthalpy change, because it speeds the forward and reverse reactions equally. Explain the role by linking lower activation energy to more successful collisions per unit time.
(i) in increasing reaction rate without being used up by the overall reaction
A catalyst increases the rate of a reaction while remaining chemically unchanged at the end of the overall reaction. It does this by taking part in one step of the mechanism and being regenerated in a later step, so its mass and identity are restored. Because it is not consumed, a small amount of catalyst can speed up a large amount of reaction. For example, manganese(IV) oxide catalyses the decomposition of hydrogen peroxide and is recovered unchanged afterwards. The catalyst does not alter the equilibrium position or the overall enthalpy change, because it accelerates the forward and reverse reactions equally. Explain the increase in rate through an alternative pathway of lower activation energy, and explain the 'not used up' point through regeneration in the mechanism.
(ii) in allowing a reaction to proceed via a different route with lower activation energy, as shown by enthalpy profile diagrams
A catalyst speeds a reaction by providing an alternative pathway whose activation energy is lower than that of the uncatalysed route. On an enthalpy profile diagram the reactants and products sit at the same enthalpy levels whether or not a catalyst is present, because a catalyst does not change the overall enthalpy change of the reaction. What changes is the height of the energy barrier between reactants and products: the catalysed curve peaks lower, so a greater fraction of collisions at a given temperature has enough energy to succeed. The catalysed route may pass through one or more intermediate stages, shown as extra humps, but each step has a lower barrier than the single uncatalysed peak. A catalyst is not used up overall and does not shift the position of equilibrium; it simply lets the system reach equilibrium faster.
(d) (i) explanation of the terms homogeneous and heterogeneous catalysts
Catalysts are classified by the phase relationship between the catalyst and the reactants. A homogeneous catalyst is in the same physical state as the reactants, so it is usually dissolved in the same solution or present in the same gas mixture; an example is acid catalysis in aqueous solution, where hydrogen ions in solution catalyse a reaction between species also in solution. A heterogeneous catalyst is in a different physical state from the reactants, typically a solid catalyst with gaseous or liquid reactants; the reaction occurs at the catalyst surface, where reactant molecules are adsorbed, react and then desorb. Recognising the phase relationship lets you explain why heterogeneous catalysis depends on surface area while homogeneous catalysis depends on the catalyst being intimately mixed with the reactants.
(ii) explanation that catalysts have great economic importance and benefits for increased sustainability by lowering temperatures and reducing energy demand from combustion of fossil fuels with resulting reduction in CO₂ emissions
A catalyst provides an alternative reaction pathway of lower activation energy, so a given rate is achieved at a lower temperature and with less heating. This matters economically because energy is a major cost in industrial processes, and a lower operating temperature can reduce fuel consumption and equipment demands. It matters for sustainability because much industrial heating relies on burning fossil fuels; using less fuel lowers energy demand and therefore reduces the CO₂ emissions associated with that combustion. A strong answer links the chain explicitly: catalyst lowers activation energy, so a lower temperature gives an acceptable rate, so less fossil fuel is burned, so less CO₂ is released. Keep the link causal rather than listing benefits separately.
(e) the techniques and procedures used to investigate reaction rates including the measurement of mass, gas volumes and time
Reaction rates can be followed by measuring a quantity that changes as the reaction proceeds and recording it against time. When a gas is produced, the mass of the reaction vessel can be measured on a balance at intervals; the loss in mass corresponds to gas escaping, so a steeper initial fall means a faster rate. Alternatively, the volume of gas collected can be measured with a gas syringe at intervals; a steeper initial rise in volume means a faster rate. In both methods time is recorded with a stopwatch, readings are taken at regular intervals, and the rate is found from the gradient or from the change in quantity per unit time. The initial rate is usually taken from the steepest part of the graph near the start.
The Boltzmann distribution
The Boltzmann distribution shows how molecular energies are spread at a given temperature. The curve starts at the origin (0,0), rises to a peak at the most probable energy, and tails off at higher energies without touching the energy axis. The area under the curve represents the total number of molecules, so it stays constant when temperature changes. Raising the temperature flattens and broadens the curve: the peak moves to higher energy and the tail extends further right, so a greater proportion of molecules have energy at or above the activation energy, Ea. This explains why reaction rate increases with temperature. The distribution applies to gases and to the energies of molecules in a sample; it does not show individual molecules changing energy over time.
(f) qualitative explanation of the Boltzmann distribution and its relationship with activation energy (see also 3.2.1 c)
A qualitative explanation of the Boltzmann distribution describes, without calculation, how molecular kinetic energies are spread at a given temperature and why only some collisions lead to reaction. Molecules in a gas or liquid have a range of energies; the distribution peaks at a moderate energy and tails off at high energy. The activation energy, Ea, is the minimum energy colliding particles need for a successful reaction, shown as a vertical line on the energy axis. Only the fraction of molecules with energy at or above Ea can react, and this fraction is small at low temperature. Raising the temperature broadens the distribution and increases the number of molecules beyond Ea, so more successful collisions occur per second and the rate rises. A catalyst lowers Ea, moving the line left so a larger fraction exceeds it.
(g) explanation, using Boltzmann distributions, of the qualitative effect on the proportion of molecules exceeding the activation energy and hence the reaction rate, for:
A Boltzmann distribution plots the number of molecules against kinetic energy at a fixed temperature. The curve starts near the origin, peaks at moderate energy and tails off at high energy; the area under it represents all the molecules. Only molecules with energy at or above the activation energy, Ea, can react, so the proportion able to react is the area under the curve to the right of Ea. Raising the temperature shifts the peak to higher energy and broadens the curve, so a much larger fraction of molecules lies beyond Ea; the rate therefore rises. Lowering the temperature moves the peak to lower energy and narrows the curve, so fewer molecules exceed Ea and the rate falls. The explanation is qualitative: describe the direction of the shift and its effect on the proportion exceeding Ea, not exact numbers.
(i) temperature changes
Temperature is one of the factors affecting reaction rate. Raising the temperature increases the average kinetic energy of the particles, so a larger proportion of molecules has energy at or above the activation energy. More frequent successful collisions result, so the rate increases. Lowering the temperature reduces the proportion exceeding the activation energy and slows the reaction. In a multiple-choice question, select the option that correctly links the temperature change to the proportion of molecules exceeding the activation energy and to the rate, and reject options that wrongly say the activation energy itself changes or that all molecules gain equal energy.
(ii) catalytic behaviour (see also 3.2.2 c).
A catalyst raises the rate of a reaction by providing an alternative route of lower activation energy, and it is not consumed overall. In homogeneous catalysis the catalyst is in the same phase as the reactants, for example Fe²⁺/Fe³⁺ ions in the peroxodisulfate–iodide reaction; in heterogeneous catalysis the catalyst is in a different phase, typically a solid surface such as iron in the Haber process, where reactant molecules adsorb, bonds weaken, reaction occurs and products desorb. The catalyst lowers the activation energy for both the forward and reverse reactions equally, so it speeds the approach to equilibrium but does not change the position of equilibrium or the yield at equilibrium. Enzymes act as biological catalysts with high specificity. A catalyst may be poisoned by impurities that block active sites, which reduces its effectiveness.
Your focus
- Explain why only some collisions lead to reaction
- Relate concentration and pressure changes to collision frequency
- Describe how a catalyst lowers activation energy
Show all 46 objectives
- Explain how increasing concentration raises reaction rate
- Relate gas pressure to particle concentration and collision frequency
- Distinguish concentration effects from temperature effects on activation energy
- Draw a tangent to a curve at a given time and calculate its gradient.
- Convert a gradient into a reaction rate with correct magnitude and units.
- Explain why the initial rate is the greatest rate observed.
- Explain how a catalyst increases reaction rate in terms of activation energy and collisions.
- Classify a catalyst as homogeneous or heterogeneous from its phase relative to the reactants.
- State the properties a catalyst does not change, such as equilibrium position and enthalpy change.
- Explain how a catalyst provides an alternative pathway of lower activation energy.
- Relate the lower activation energy to an increased rate of reaction.
- Explain that a catalyst is regenerated and not used up by the overall reaction.
- State that a catalyst does not change the equilibrium position or the overall enthalpy change.
- Explain how a catalyst increases the rate of reaction.
- Explain that a catalyst is regenerated and not used up by the overall reaction.
- State that a catalyst does not change the equilibrium position or the overall enthalpy change.
- Interpret an enthalpy profile diagram to identify the activation energy of catalysed and uncatalysed routes.
- Explain how a catalyst increases reaction rate by providing a route of lower activation energy.
- Distinguish between the effect of a catalyst on activation energy and on the overall enthalpy change.
- Define homogeneous and heterogeneous catalysts in terms of the physical states of catalyst and reactants.
- Classify a given catalytic system as homogeneous or heterogeneous.
- Explain that heterogeneous catalysis occurs at the catalyst surface.
- Explain how a catalyst lowers the activation energy and allows a lower operating temperature
- Describe the economic benefits of reduced energy demand in industrial processes
- Trace the link from reduced fossil-fuel combustion to reduced CO₂ emissions
- Describe how mass loss and gas volume can be measured over time to follow a reaction
- Explain how rate is calculated from the change in a measured quantity per unit time
- Interpret rate graphs to compare initial rates of reaction
- Sketch and interpret a Boltzmann distribution curve, identifying the most probable energy.
- Explain how increasing temperature changes the shape of the distribution and the proportion of molecules with energy ≥ Ea.
- Relate the area under the curve beyond Ea to the rate of a reaction.
- Explain qualitatively why only a fraction of collisions are successful
- Relate the Boltzmann distribution to activation energy at a given temperature
- Explain how temperature and catalysts change the fraction of molecules exceeding Ea
- Sketch and interpret a Boltzmann distribution showing the proportion of molecules exceeding the activation energy.
- Explain qualitatively how raising or lowering the temperature changes the proportion of molecules exceeding the activation energy.
- Relate the changed proportion exceeding the activation energy to the reaction rate.
- Identify the correct effect of a temperature change on the proportion of molecules exceeding the activation energy.
- Link the changed proportion exceeding the activation energy to the reaction rate.
- Reject options that wrongly change the activation energy or assume equal energy gain.
- Explain how a catalyst increases reaction rate by lowering activation energy.
- Distinguish homogeneous from heterogeneous catalysis using the phases of catalyst and reactants.
- Explain why a catalyst does not change the position of equilibrium or the equilibrium yield.
Reaction rates exam tips
Marking Points
- States that particles must collide for a reaction to occur
- Explains that only collisions with energy at least equal to the activation energy are successful
- Relates increased concentration or pressure to more frequent collisions per unit volume
- Identifies that a catalyst lowers the activation energy by providing an alternative route
- States that increasing concentration increases the number of particles per unit volume
- Links the greater particle density to a higher frequency of collisions
- Explains that a higher frequency of successful collisions increases the rate
- Explains that increasing the pressure of a gas is equivalent to increasing its concentration
- Selects a tangent to the curve at the specified time rather than a chord between two points on the curve
- Divides the change in the physical quantity by the corresponding change in time to obtain the gradient
- Reports the rate as the magnitude of the gradient, giving a positive value even when the quantity decreases
- Derives the units of the rate from the units of the two axes, for example mol dm⁻³ s⁻¹ or cm³ s⁻¹
- Identifies that the steepest gradient, and therefore the greatest rate, occurs at the start of the reaction
- States that a catalyst provides an alternative reaction pathway with a lower activation energy
- Explains that a greater proportion of collisions has energy at or above the activation energy, increasing the rate of successful collisions
- States that the catalyst is not used up overall and is regenerated during the reaction
- Distinguishes a homogeneous catalyst, in the same phase as the reactants, from a heterogeneous catalyst, in a different phase
- States that a catalyst does not change the position of equilibrium or the enthalpy change of the reaction
- States that a catalyst provides an alternative reaction pathway.
- Explains that the alternative pathway has a lower activation energy than the uncatalysed route.
- Links the lower activation energy to a greater proportion of collisions having sufficient energy, so the rate increases.
- States that the catalyst is regenerated and is not used up by the overall reaction.
- States that a catalyst does not change the position of equilibrium or the overall enthalpy change.
- States that a catalyst increases the rate of reaction.
- Explains that the catalyst is not used up because it is regenerated in a later step of the mechanism.
- Links the increased rate to an alternative pathway of lower activation energy.
- States that a small amount of catalyst can catalyse a large amount of reaction because it is not consumed.
- States that the catalyst does not change the equilibrium position or the overall enthalpy change.
- Identifies that a catalyst provides an alternative reaction pathway with a lower activation energy than the uncatalysed route.
- States that the enthalpy change of the reaction is unchanged by the catalyst, so reactants and products occupy the same levels on the profile.
- Reads the activation energy from an enthalpy profile as the energy difference between the reactants' level and the peak of the curve.
- Explains that a lower activation energy means a greater proportion of collisions possess sufficient energy at the same temperature.
- Recognises that a catalysed route may involve intermediate stages shown as additional peaks, each with a lower barrier than the uncatalysed peak.
- Defines a homogeneous catalyst as one in the same physical state as the reactants.
- Defines a heterogeneous catalyst as one in a different physical state from the reactants.
- Gives a valid example of homogeneous catalysis in which catalyst and reactants share a phase, such as an aqueous acid catalyst.
- Gives a valid example of heterogeneous catalysis in which a solid catalyst acts on gaseous or liquid reactants.
- Explains that heterogeneous catalysis takes place at the surface of the catalyst, where reactants are adsorbed.
- States that a catalyst provides an alternative pathway with a lower activation energy
- Explains that the lower activation energy allows an acceptable rate at a lower temperature
- Links lower energy demand to reduced combustion of fossil fuels
- Connects reduced fossil-fuel combustion to lower CO₂ emissions
- Identifies economic importance as reduced energy costs in industrial processes
- Selects measurement of mass lost from the reaction vessel when a gas is produced
- Selects measurement of gas volume collected, for example with a gas syringe, when a gas is produced
- Records the measured quantity at regular time intervals using a stopwatch
- Calculates rate from the change in mass or volume divided by the time taken
- Uses the steepest initial part of the graph to compare initial rates
- Describes the curve starting at the origin and rising to a peak before tailing off at high energy.
- Identifies the peak as the most probable energy of the molecules.
- States that the area under the curve represents the total number of molecules and is constant.
- Explains that increasing temperature moves the peak to higher energy and broadens the tail.
- Links the greater area beyond Ea at higher temperature to a higher reaction rate.
- Describes the spread of molecular energies with a peak and a high-energy tail
- Defines activation energy as the minimum collision energy needed for a successful reaction
- Explains that only molecules with energy at or above Ea react on collision
- Explains that raising temperature increases the fraction of molecules exceeding Ea and so increases rate
- Explains that a catalyst lowers Ea and so increases the fraction of molecules able to react
- Describes the shape of a Boltzmann distribution as number of molecules against kinetic energy, starting near the origin, peaking at moderate energy and tailing off at high energy.
- Identifies the area under the curve to the right of the activation energy as the proportion of molecules with enough energy to react.
- Explains that raising the temperature shifts the peak to higher energy and broadens the distribution, increasing the proportion of molecules exceeding the activation energy.
- Links the increased proportion exceeding the activation energy to a higher frequency of successful collisions and hence a greater reaction rate.
- Explains that lowering the temperature shifts the peak to lower energy and narrows the distribution, decreasing the proportion exceeding the activation energy and lowering the rate.
- Selects the option stating that raising the temperature increases the proportion of molecules with energy at or above the activation energy.
- Selects the option linking the increased proportion exceeding the activation energy to a higher rate of successful collisions.
- Rejects options claiming that raising the temperature lowers the activation energy.
- Rejects options claiming that heating gives every molecule the same increase in energy.
- States that a catalyst increases the rate of reaction by providing an alternative pathway of lower activation energy.
- Distinguishes homogeneous catalysis, where the catalyst is in the same phase as the reactants, from heterogeneous catalysis, where the phases differ.
- Explains that a catalyst lowers the activation energy of both forward and reverse reactions equally, so equilibrium position and yield are unchanged.
- Describes heterogeneous catalysis in terms of adsorption of reactants onto the solid surface, weakening of bonds, reaction and desorption of products.
- Identifies that a catalyst is not used up overall and can be recovered chemically unchanged at the end of the reaction.
- Explains that catalyst poisoning occurs when impurities block active sites and reduce catalytic effectiveness.
Examiner Tips
- 💡Link each factor to collision frequency or to the proportion of successful collisions
- 💡Use the phrase activation energy precisely rather than saying energy is needed vaguely
- 💡Check whether the question asks about frequency of collisions or about successful collisions
- 💡Always connect concentration or pressure to collision frequency, then to rate
- 💡For gases, explain that higher pressure means the same particles occupy a smaller volume
- 💡Keep activation energy constant when explaining concentration effects
- 💡Check the axis labels first and write down the units of the gradient before calculating.
- 💡Show the two coordinate pairs you read from the tangent so the division is visible.
- 💡If asked for initial rate, draw the tangent at time zero where the curve is steepest.
- 💡Link the lower activation energy explicitly to the proportion of collisions with sufficient energy.
- 💡Use the words 'alternative pathway' and 'regenerated' to hit the key ideas.
- 💡When asked about equilibrium, state that the catalyst affects rate only, not position.
- 💡Use the phrase 'alternative pathway of lower activation energy' rather than 'lowers the activation energy'.
- 💡Distinguish clearly between rate effects and equilibrium effects when explaining a catalyst.
- 💡Support the explanation with a named example, such as a solid catalyst adsorbing reactants onto its surface.
- 💡Check that each option in a multiple-choice question matches the definition of a catalyst before selecting it.
- 💡Use a named example, such as manganese(IV) oxide in the decomposition of hydrogen peroxide, to show the catalyst is recovered unchanged.
- 💡Separate the two ideas in the statement: the increase in rate and the fact that the catalyst is not used up.
- 💡Avoid claiming that a catalyst changes the enthalpy change or the equilibrium position.
- 💡Read each multiple-choice option carefully to check whether it describes regeneration or consumption.
- 💡Label the axes and mark the activation energy as the vertical gap from the reactants' level to the peak before comparing curves.
- 💡Compare catalysed and uncatalysed curves on the same diagram so the unchanged reactant and product levels are visible.
- 💡Link the lower peak explicitly to the proportion of collisions with energy greater than the activation energy.
- 💡Check whether the question asks about rate or about equilibrium position, because a catalyst affects only the former.
- 💡State the physical state of the catalyst and of the reactants explicitly when classifying a system.
- 💡Use a familiar industrial or laboratory example to anchor each definition.
- 💡For heterogeneous systems, mention adsorption at the surface to show why surface area matters.
- 💡Read the question carefully to see whether it asks for a definition, an example, or both.
- 💡Write the causal chain in order: lower activation energy, lower temperature, less fossil fuel burned, less CO₂ emitted
- 💡Use the phrase 'alternative pathway of lower activation energy' rather than saying a catalyst 'lowers the activation energy of the reaction' loosely
- 💡Tie economic importance to energy costs and sustainability to emissions, so both clauses of the statement are addressed
- 💡State the apparatus and the quantity measured, then say how rate is obtained from the data
- 💡Use 'change in mass or volume per unit time' to define rate precisely
- 💡When comparing experiments, compare initial gradients rather than final values
- 💡Sketch the curve starting at the origin and label the axes clearly.
- 💡Mark the activation energy Ea on the energy axis and shade the area beyond it.
- 💡Compare two curves at different temperatures on the same axes to show the shift in the peak and tail.
- 💡Link each change on the graph to a change in the number of successful collisions per second
- 💡Use the phrase 'energy greater than or equal to the activation energy' to make the threshold explicit
- 💡Contrast temperature change (curve shape changes, Ea fixed) with catalyst change (Ea lowered, curve unchanged)
- 💡Sketch the axes and curve first, mark the activation energy and shade the area beyond it, then explain the shift in words.
- 💡Use the phrase 'proportion of molecules with energy greater than or equal to the activation energy' to keep the explanation precise.
- 💡Finish by connecting the changed proportion to collision frequency and reaction rate so the causal chain is complete.
- 💡Read every option and eliminate those that alter the activation energy rather than the proportion exceeding it.
- 💡Look for the option that names both the proportion exceeding the activation energy and the effect on rate.
- 💡Check the direction of the temperature change before choosing between faster and slower rate options.
- 💡Read the stem carefully to identify whether the question asks about rate, equilibrium position or yield, because a catalyst affects only rate and time to equilibrium.
- 💡Link the type of catalysis to the physical state of catalyst and reactants before choosing an option.
- 💡Eliminate options that claim a catalyst is consumed or that it shifts the position of equilibrium.
- 💡Recall a named example such as iron in the Haber process to check heterogeneous surface catalysis reasoning.
Common Mistakes
- Claims that any collision causes reaction; correct this by requiring sufficient energy and correct orientation
- States that increasing concentration increases the activation energy; correct this by linking concentration to collision frequency
- Assumes temperature only increases collision frequency; correct this by adding the greater proportion of particles exceeding the activation energy
- States that increasing concentration lowers the activation energy; correct this by linking concentration to collision frequency only
- Confuses pressure with temperature; correct this by explaining that pressure changes particle concentration in a gas
- Claims rate increases because particles move faster when concentration rises; correct this by attributing faster motion to temperature, not concentration
- Uses a chord joining two points on the curve instead of a tangent at the required time; draw the tangent at that single point and read two points from the tangent line
- Reports a negative rate when concentration falls; state the rate as the positive magnitude of the gradient
- Omits or misstates the units; build the units from the axis labels, dividing the quantity unit by the time unit
- Reads the tangent over a very short interval; choose two widely separated points on the tangent to reduce error
- Claims a catalyst increases the yield or shifts the equilibrium position; state that it speeds the forward and reverse reactions equally and leaves the equilibrium position unchanged
- Says a catalyst lowers the enthalpy change of reaction; state that it lowers only the activation energy
- Describes a catalyst as being used up; state that it is regenerated and not consumed overall
- Confuses homogeneous and heterogeneous catalysts; match each term to whether the catalyst shares the phase of the reactants
- States that a catalyst lowers the activation energy of the existing pathway; correct this by saying it provides an alternative pathway of lower activation energy.
- Claims that a catalyst increases the yield or shifts the equilibrium position; correct this by noting that it speeds forward and reverse reactions equally and leaves equilibrium unchanged.
- Says a catalyst is used up in the reaction; correct this by explaining that it is regenerated in a later step and its mass is unchanged overall.
- Describes a catalyst as increasing the energy of reactant particles; correct this by explaining that it changes the pathway, not the energy of the particles.
- States that the catalyst is consumed during the reaction; correct this by explaining that it is regenerated and recovered unchanged.
- Claims that a catalyst increases the equilibrium yield; correct this by noting that it speeds forward and reverse reactions equally.
- Says a catalyst lowers the activation energy of the existing pathway; correct this by saying it provides an alternative pathway of lower activation energy.
- Assumes a large mass of catalyst is needed; correct this by explaining that a small amount can catalyse a large amount of reaction because it is regenerated.
- Claims that a catalyst lowers the enthalpy change of the reaction; correct this by stating that only the activation energy is lowered and the overall enthalpy change stays the same.
- Describes a catalyst as increasing the energy of the colliding particles; correct this by explaining that the alternative route needs less energy to reach the transition state.
- Assumes the catalysed curve must be a single lower peak; correct this by allowing for intermediate stages that appear as extra humps on the profile.
- States that a catalyst shifts the equilibrium position to favour products; correct this by noting that equilibrium is reached faster but its position is unchanged.
- Confuses the two terms by calling a solid catalyst with gaseous reactants homogeneous; correct this by checking whether catalyst and reactants share a physical state.
- Defines the terms by whether the catalyst dissolves rather than by the physical states involved; correct this by basing the definition on the phase relationship.
- Describes a heterogeneous catalyst as reacting in the bulk of the gas rather than at its surface; correct this by locating the reaction at the catalyst surface.
- Omits an example when asked to explain the terms; correct this by supplying one clear example of each type.
- Claims that a catalyst increases the yield of an equilibrium reaction; correct this by stating that a catalyst speeds the approach to equilibrium without changing the position of equilibrium
- Says a catalyst is used up in the reaction; correct this by stating that a catalyst is not consumed overall and can be used repeatedly
- Lists sustainability benefits without linking them to lower temperature and energy demand; correct this by tracing the causal chain from activation energy to CO₂ emissions
- Measures mass gained when a gas is escaping; correct this by measuring the decrease in mass as gas leaves the vessel
- Takes a single reading and calls it the rate; correct this by recording the quantity at intervals against time and finding the change per unit time
- Compares total gas volume produced rather than the rate; correct this by comparing the gradient or the initial rate, not the final volume
- Starts the curve high on the y-axis at zero energy; begin the curve at the origin (0,0).
- Labels the peak as the average energy; label it as the most probable energy.
- Claims the curve touches the energy axis at high energy; keep the tail asymptotic and never crossing the axis.
- Says the total area changes with temperature; keep the area constant and change only the shape.
- Claims that raising temperature increases the activation energy; keep Ea fixed and explain that more molecules now exceed it
- States that all collisions lead to reaction; restrict successful collisions to those with energy at or above Ea and correct orientation
- Says a catalyst increases the energy of the molecules; explain instead that a catalyst provides an alternative route with lower Ea
- Describes the distribution as a single energy value; describe a range of energies with a peak and a tail
- States that raising the temperature increases the activation energy; keep the activation energy fixed and describe the shift of the distribution instead.
- Claims that all molecules gain energy equally on heating; describe a broader spread with a larger proportion above the fixed activation energy.
- Omits the link from the proportion exceeding the activation energy to collision frequency and rate; state that link explicitly.
- Draws or describes the curve crossing the energy axis at a positive value; start the curve near the origin.
- Chooses an option saying the activation energy decreases on heating; keep the activation energy fixed and change the proportion exceeding it.
- Chooses an option saying all molecules gain equal energy; recognise that heating broadens the spread of energies.
- Chooses an option that changes the proportion exceeding Ea but omits the effect on rate; require the full causal link.
- Claims that a catalyst increases the equilibrium yield; correct this by stating that a catalyst changes only the rate of attainment of equilibrium, not its position.
- Describes a catalyst as being used up in the reaction; correct this by stating that it is not consumed overall and is regenerated.
- Confuses homogeneous and heterogeneous catalysis; correct this by checking whether catalyst and reactants share the same physical phase.
- States that a catalyst lowers the activation energy of only the forward reaction; correct this by noting that both directions are lowered equally.