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    Real operational amplifiers (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    Real operational amplifiers (op-amps) are non-ideal devices that deviate from the ideal model due to finite open-loop gain, input bias currents, input offset voltage, and limited bandwidth. In AQA A-Level Physics, students must understand how these imperfections affect circuit performance and how to apply negative feedback to minimise their impact in practical amplifier designs.

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    Real operational amplifiers (A-level only) explained

    Real operational amplifiers (A-level only) covers 3 specification points, including Limitations of real operational amplifiers.

    Read the full explanation

    and Frequency response curve.. Open a point below for its explanation and revision guidance.

    Limitations of real operational amplifiers.

    Real operational amplifiers depart from the ideal model in several ways that affect circuit performance. Open-loop gain is finite, input impedance is not infinite, output impedance is not zero, and the output cannot swing beyond the supply rails, so saturation occurs. Real devices also have a finite gain-bandwidth product, meaning gain falls as frequency rises, and they exhibit offset voltage, bias currents and slew-rate limits. You should be able to explain how each limitation changes the behaviour of a practical amplifier compared with predictions from the ideal relationships, and suggest how circuit design can reduce the effects, for example by choosing a device with a higher gain-bandwidth product or by keeping signals within the linear output range.

    Frequency response curve.

    A frequency response curve plots the gain of an operational amplifier against the frequency of the input signal, usually on logarithmic axes. At low frequencies the gain is approximately constant at the open-loop value, then falls as frequency rises. The curve shows where gain has dropped by 3 dB from its low-frequency value; this is the bandwidth limit, and the product of gain and bandwidth is roughly constant. For a real op-amp, stray capacitance and internal compensation cause this roll-off. To obtain the curve, apply a small sinusoidal input of fixed amplitude, vary its frequency across a wide range, and measure the output amplitude with an oscilloscope or meter, calculating gain as output amplitude divided by input amplitude.

    gain × bandwidth = constant for a given device.

    For a given operational amplifier, the product of voltage gain and bandwidth is approximately constant. This means that if you increase the closed-loop gain by reducing negative feedback, the bandwidth over which that gain is maintained becomes proportionally smaller, and vice versa. The constant is set by the device's gain–bandwidth product, often quoted in hertz. For example, an op-amp with a gain–bandwidth product of 1 × 10⁶ Hz gives a gain of 100 up to about 1 × 10⁴ Hz, or a gain of 10 up to about 1 × 10⁵ Hz. The relationship applies while the amplifier is operating within its linear region and is a useful design trade-off between amplification and frequency range.

    Your focus

    1. Describe how finite gain, non-zero output impedance and supply rail limits affect the output of a real op-amp circuit.
    2. Explain the effects of gain-bandwidth product, offset voltage, bias current and slew rate on practical amplifier performance.
    3. Suggest appropriate design or device choices that reduce the impact of real op-amp limitations.
    Show all 9 objectives
    1. Sketch and interpret a frequency response curve for a real op-amp.
    2. Explain why gain falls at high frequency and identify the 3 dB point.
    3. Describe a practical procedure to obtain a frequency response curve.
    4. State and apply the gain–bandwidth relationship for a given op-amp.
    5. Calculate a new bandwidth when the gain is changed.
    6. Explain why gain and bandwidth trade off against each other in real op-amps.

    Which command word is this?

    You must use the correct formula and show all working. Numerical answers should be given to an appropriate number of significant figures, typically 2 or 3. Units must be included. For real op-amp calculations, use the exact formulas where necessary, not just ideal approximations.

    Real operational amplifiers (A-level only) exam tips

    Topic Overview

    Real operational amplifiers differ from the ideal model in several key ways: they have finite open-loop gain, non-zero input bias currents, input offset voltage, and limited bandwidth. In AQA A-Level Physics, you need to understand how these non-idealities affect the performance of amplifier circuits and how negative feedback can mitigate their effects. This topic builds on the ideal op-amp principles and prepares you for practical circuit design and analysis.

    Understanding real op-amp limitations is crucial for interpreting experimental data and for designing circuits that meet specific requirements, such as low offset or high bandwidth. It also connects to broader concepts like feedback, stability, and signal-to-noise ratio. Mastery of this topic will enable you to answer synoptic questions that link electronics to other areas of physics, such as communication systems and instrumentation.

    Key Concepts
    • →Finite open-loop gain: Real op-amps have a large but finite gain (typically 10^5 to 10^7), which causes the closed-loop gain to be slightly less than the ideal value and introduces a small differential input voltage.
    • →Input offset voltage (Vos): The differential DC voltage required between the inputs to make the output zero. It appears amplified at the output by the noise gain, causing an output offset even with zero input.
    • →Input bias current (Ib): The average DC current flowing into the input terminals. It flows through the feedback network, creating an additional output offset voltage. It can be minimised by matching the resistances seen by both inputs.
    • →Bandwidth limitations: Real op-amps have a finite gain-bandwidth product (GBP), meaning the open-loop gain decreases with frequency. This limits the maximum frequency at which the amplifier can provide a given closed-loop gain.
    • →Slew rate: The maximum rate of change of the output voltage, typically measured in V/μs. It limits the amplifier's ability to respond to fast changes in input, causing distortion in large-signal high-frequency applications.
    Marking Points
    • Explains that finite open-loop gain means the virtual earth approximation is only approximate, so measured gain is slightly lower than the ideal calculated value.
    • Describes saturation as the output voltage being limited by the positive and negative supply rails, so the output clips rather than following the input further.
    • Explains that finite gain-bandwidth product causes the available gain to fall as signal frequency increases, limiting performance at high frequencies.
    • Identifies input offset voltage or input bias current as causes of a small unwanted output voltage even when the input is zero.
    • Describes slew rate as a limit on how quickly the output voltage can change, causing distortion of fast or large signals.
    • A frequency response curve shows how voltage gain varies with input signal frequency for a given op-amp configuration.
    • At low frequencies the gain is approximately constant and equal to the open-loop or closed-loop value, depending on the circuit.
    • As frequency increases, gain falls; the upper limit is often quoted where gain has fallen by 3 dB from its low-frequency value.
    • The bandwidth is the range of frequencies over which the gain remains within 3 dB of its maximum, and it is linked to the gain by gain × bandwidth = constant.
    • A practical method is to apply a fixed-amplitude sine wave, vary frequency, measure input and output amplitudes, and plot gain against frequency.
    • Logarithmic axes or a Bode-style plot make the constant gain region and the roll-off easier to identify.
    • The gain–bandwidth product is approximately constant for a given op-amp device.
    • Increasing closed-loop gain reduces the available bandwidth in proportion.
    • The constant may be found from the open-loop gain and the frequency at which gain has fallen by 3 dB.
    • The relationship allows the bandwidth to be predicted for a chosen gain, or the gain to be predicted for a required bandwidth.
    • The product is valid while the op-amp remains within its linear operating region and is not slew-rate limited.
    • Typical units are hertz, since gain is a dimensionless ratio and bandwidth is a frequency.
    Examiner Tips
    • 💡Link each limitation to a specific observable effect on the output waveform, such as clipping, reduced amplitude or distortion.
    • 💡Use comparative language, for example ideal predicts one value while the real circuit gives a slightly different value, to show understanding.
    • 💡When asked to suggest improvements, refer to device choice or circuit operating conditions rather than vague statements about better components.
    • 💡Label both axes with quantity and unit, and state whether gain is a ratio or in decibels.
    • 💡When describing a measurement, specify fixed input amplitude, varied frequency, and measurement of both input and output.
    • 💡Link the shape of the curve to the gain–bandwidth relationship rather than treating it as an isolated graph.
    • 💡Write the relationship as gain × bandwidth = constant before substituting values.
    • 💡Check that the calculated bandwidth is a frequency and give the unit hertz.
    • 💡Use the relationship to compare two configurations of the same op-amp rather than comparing different devices.
    • 💡Always state the ideal assumptions when calculating gains, and then discuss how real op-amp parameters would alter the result. This shows deeper understanding and can earn synoptic marks.
    • 💡When calculating output offset due to bias current, remember that the current flows through the feedback resistor (and any input resistor) creating a voltage that is then amplified. Use the correct resistor value depending on the configuration.
    • 💡For bandwidth questions, use the gain-bandwidth product: GBP = A × f. The closed-loop bandwidth is GBP / closed-loop gain. Be careful with units (Hz, kHz, MHz).
    Common Mistakes
    • Treating the op-amp output as able to exceed the supply rails; the correction is to recognise that saturation clamps the output near the rail voltages.
    • Assuming gain is constant at all frequencies; the correction is to apply the gain-bandwidth product idea so that higher gain reduces usable bandwidth.
    • Ignoring input offset voltage when explaining a non-zero output for zero input; the correction is to attribute it to device imperfections such as offset and bias current.
    • Plotting output amplitude rather than gain: the correction is to divide output amplitude by input amplitude at each frequency so the curve describes the device rather than the test signal.
    • Assuming the curve is flat at all frequencies: the correction is to recognise the high-frequency roll-off caused by internal capacitance and compensation.
    • Reading the bandwidth at the point where gain reaches zero: the correction is to use the 3 dB reduction point from the low-frequency gain.
    • Adding gains and bandwidths instead of multiplying: the correction is to use the product gain × bandwidth and keep it constant.
    • Treating the constant as applying to all op-amps: the correction is to recognise that each device has its own gain–bandwidth product.
    • Using the signal frequency rather than the bandwidth limit: the correction is to identify the bandwidth as the range up to the 3 dB point.
    • Students often think that the input impedance of a real op-amp is infinite, but it is actually finite (typically 10^6 to 10^12 Ω). This can cause loading effects on the input signal source.
    • Many believe that the output impedance is zero, but real op-amps have a small non-zero output impedance (typically a few ohms to tens of ohms), which can cause voltage drops when driving heavy loads.
    • Students frequently ignore the effect of input offset voltage and bias current in DC-coupled amplifiers, leading to significant output errors in precision applications.
    Revision Plan
    1. 1Start by reviewing the ideal op-amp model and the standard configurations. Ensure you can derive the gain formulas from first principles using Kirchhoff's laws and the virtual earth approximation.
    2. 2Learn the definitions and typical values of real op-amp parameters: open-loop gain, input offset voltage, input bias current, input offset current, slew rate, and gain-bandwidth product.
    3. 3Work through calculations involving finite open-loop gain, output offset voltage due to Vos and Ib, and bandwidth limitations. Practice using the exact formulas and compare with ideal results.
    4. 4Study practical methods to minimise errors: using a compensation resistor for bias current, choosing low-offset op-amps, and applying negative feedback to extend bandwidth.
    5. 5Attempt past paper questions on real op-amps, focusing on structured questions that require both calculation and explanation. Review mark schemes to understand the level of detail required.
    Exam Question Types
    • 📋Calculation of closed-loop gain including finite open-loop gain: You may be asked to calculate the actual gain using the formula G = A/(1 + A/G_ideal) and compare it with the ideal gain. Show all steps and comment on the difference.
    • 📋Calculation of output offset voltage: Given Vos and Ib, calculate the total output offset for a given circuit. Remember to use the noise gain for Vos and the appropriate resistor for Ib. Be careful with units.
    • 📋Explanation of bandwidth limitations: Describe how the gain-bandwidth product affects the performance of an amplifier at high frequencies. You may be asked to calculate the maximum frequency for a given gain.
    • 📋Practical circuit design: Suggest modifications to a circuit to reduce offset errors, such as adding a compensation resistor or using a chopper-stabilised op-amp. Explain why these methods work.
    Command Word Expectations (AQA)
    Calculate

    You must use the correct formula and show all working. Numerical answers should be given to an appropriate number of significant figures, typically 2 or 3. Units must be included. For real op-amp calculations, use the exact formulas where necessary, not just ideal approximations.

    Explain

    You must provide a detailed account of why a phenomenon occurs or how a parameter affects circuit performance. Use correct terminology and refer to specific op-amp characteristics. For example, explain how input bias current causes an output offset voltage by flowing through the feedback resistor.

    Describe

    You must give a clear, factual account of the characteristics or effects of real op-amp parameters. No calculation is required, but you should include typical values or ranges where relevant. For example, describe the effect of finite open-loop gain on the closed-loop gain of an amplifier.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often assume the op-amp is ideal and ignore the effect of finite open-loop gain on the gain of a non-inverting amplifier, leading to inaccurate calculations.
    ❌ Weak Answer (Loses Marks):The gain of a non-inverting amplifier is just 1 + Rf/Rin, so the gain is exactly 11 for Rf = 10kΩ and Rin = 1kΩ.
    Example improved answer:For a non-inverting amplifier, the ideal closed-loop gain is 1 + Rf/Rin = 11. However, with a real op-amp having finite open-loop gain A, the actual gain is A/(1 + A/(1 + Rf/Rin)). For A = 100,000, the actual gain is approximately 10.9989, which is very close to 11 but not exact. The small error arises because the differential input voltage is not zero but Vout/A.
    Examiner Tip: Always state that the ideal gain formula assumes infinite open-loop gain. For high-precision work, mention that real op-amps have finite gain, causing a slight reduction in closed-loop gain. Use the exact formula if required, but in most A-level questions the ideal approximation is acceptable unless stated otherwise.
    Pitfall: Students confuse input offset voltage with input bias current, or forget that these parameters cause output voltage errors even when the input is zero.
    ❌ Weak Answer (Loses Marks):Input offset voltage is the same as input bias current, and it only matters when there is a signal.
    Example improved answer:Input offset voltage (Vos) is the differential DC voltage that must be applied between the input terminals to make the output zero. Input bias current (Ib) is the average DC current flowing into the input terminals. Both cause output errors: Vos appears amplified at the output by the noise gain, while Ib flows through the feedback network creating an additional voltage drop. For example, with Vos = 1 mV and noise gain = 11, the output offset is 11 mV. With Ib = 10 nA and a 10 kΩ feedback resistor, the additional offset is 0.1 mV.
    Examiner Tip: Clearly distinguish between voltage and current parameters. Remember that offset errors are present even with zero input signal. Use the noise gain (1 + Rf/Rin) for non-inverting amplifiers to calculate the output offset due to Vos.
    Step-by-Step Worked Solutions

    Question: A non-inverting amplifier uses an op-amp with an open-loop gain of 200,000 and a feedback network with Rf = 100 kΩ and Rin = 10 kΩ. Calculate the ideal closed-loop gain and the actual closed-loop gain, assuming the op-amp is otherwise ideal.

    1. 1.Step 1: Identify given values: A = 200,000, Rf = 100 kΩ, Rin = 10 kΩ.
    2. 2.Step 2: Calculate ideal closed-loop gain: G_ideal = 1 + Rf/Rin = 1 + 100/10 = 11.
    3. 3.Step 3: Use the exact formula for non-inverting amplifier gain: G_actual = A / (1 + A/G_ideal) = 200,000 / (1 + 200,000/11) = 200,000 / (1 + 18181.818) = 200,000 / 18182.818 ≈ 10.9994.
    4. 4.Step 4: State final conclusion: The ideal gain is 11.00, and the actual gain is approximately 10.999, a difference of about 0.001%.
    Final Answer: Ideal gain = 11.0; actual gain ≈ 10.999 (to 3 d.p.). The finite open-loop gain causes a negligible reduction in this case.

    Question: An op-amp has an input offset voltage of 2 mV and an input bias current of 50 nA. It is used in a non-inverting amplifier with Rf = 1 MΩ and Rin = 100 kΩ. Calculate the total output offset voltage due to these two parameters.

    1. 1.Step 1: Identify given values: Vos = 2 mV, Ib = 50 nA, Rf = 1 MΩ, Rin = 100 kΩ.
    2. 2.Step 2: Calculate noise gain: G_noise = 1 + Rf/Rin = 1 + 1,000,000/100,000 = 11.
    3. 3.Step 3: Calculate output offset due to Vos: Vout_offset_Vos = Vos × G_noise = 2 mV × 11 = 22 mV.
    4. 4.Step 4: Calculate output offset due to Ib: The bias current flows through the parallel combination of Rf and Rin (since the other input is grounded). R_parallel = (Rf × Rin)/(Rf + Rin) = (1M × 100k)/(1.1M) ≈ 90.91 kΩ. Vout_offset_Ib = Ib × R_parallel × G_noise? Actually, the bias current at the inverting input flows through Rf, creating a voltage drop Ib × Rf, which is then amplified by the noise gain? More accurately, the output offset due to bias current is Ib × Rf (for the inverting input) if the non-inverting input is grounded via a resistor. However, in a simple analysis, the output offset due to bias current is Ib × Rf. But this is not multiplied by the noise gain because it appears directly at the output? Let's derive: The voltage at the inverting input is V- = Vout × Rin/(Rf+Rin). The current through Rf is (Vout - V-)/Rf = Ib. Solving gives Vout = Ib × Rf. So Vout_offset_Ib = 50 nA × 1 MΩ = 50 mV. But this is for the case where the non-inverting input is grounded directly. If there is a bias current compensation resistor, it changes. For simplicity, assume no compensation. So total offset = 22 mV + 50 mV = 72 mV.
    5. 5.Step 5: State final conclusion: The total output offset voltage is approximately 72 mV.
    Final Answer: Total output offset voltage ≈ 72 mV (22 mV from Vos, 50 mV from Ib).
    Active Recall Memory Test
    What is input offset voltage and how does it affect the output of an op-amp?
    Key Fact: Input offset voltage (Vos) is the differential DC voltage that must be applied between the input terminals to make the output zero. It appears amplified at the output by the noise gain (1 + Rf/Rin for non-inverting), causing an output offset voltage even when the input signal is zero.
    Define gain-bandwidth product and state its significance for real op-amps.
    Key Fact: The gain-bandwidth product (GBP) is the product of the open-loop gain and the frequency at which it is measured. It is constant for a given op-amp, meaning that as the closed-loop gain increases, the bandwidth decreases. It limits the maximum frequency at which a given gain can be achieved.
    How can the effect of input bias current be minimised in an op-amp circuit?
    Key Fact: The effect of input bias current can be minimised by adding a compensation resistor equal to the parallel combination of Rf and Rin in series with the non-inverting input. This ensures that both inputs see the same DC resistance, so the bias currents produce equal voltage drops, which cancel out.
    What is slew rate and when does it become important?
    Key Fact: Slew rate is the maximum rate of change of the output voltage, usually expressed in V/μs. It becomes important when the op-amp is required to produce large, fast-changing output signals, such as in high-frequency or high-amplitude applications. If the required rate of change exceeds the slew rate, the output will distort.
    Frequently Asked Questions
    What is the difference between ideal and real operational amplifiers?
    An ideal op-amp has infinite open-loop gain, infinite input impedance, zero output impedance, infinite bandwidth, and zero offset voltage and bias current. A real op-amp has finite values for all these parameters: open-loop gain is typically 10^5 to 10^7, input impedance is finite (10^6 to 10^12 Ω), output impedance is small but non-zero, bandwidth is limited, and there are small offset voltages and bias currents. These non-idealities affect circuit performance and must be considered in precision applications.
    How do I calculate the output offset voltage due to input bias current?
    The output offset voltage due to input bias current depends on the circuit configuration. For an inverting amplifier, the bias current at the inverting input flows through the feedback resistor Rf, creating a voltage drop Ib × Rf, which appears directly at the output. For a non-inverting amplifier, the same applies if the non-inverting input is grounded directly. If a compensation resistor is used, the calculation changes. Always check the circuit diagram and identify the path of the bias current.
    What is the gain-bandwidth product and how do I use it?
    The gain-bandwidth product (GBP) is a constant for a given op-amp, equal to the product of the open-loop gain and the frequency at which it is measured. It is typically specified in the datasheet. To find the closed-loop bandwidth for a given gain, divide the GBP by the closed-loop gain. For example, if GBP = 1 MHz and closed-loop gain = 100, the bandwidth is 10 kHz. This means the amplifier can provide that gain up to 10 kHz before the gain starts to roll off.
    Why does my op-amp circuit have a DC offset even when the input is zero?
    A DC offset at the output with zero input is usually caused by the op-amp's input offset voltage and input bias current. The input offset voltage is amplified by the noise gain, and the input bias current flows through the feedback network, creating an additional voltage. To reduce this, you can use an op-amp with lower offset voltage and bias current, or add a compensation resistor to balance the bias currents. In precision applications, chopper-stabilised or auto-zero op-amps are used.
    What is slew rate and how does it affect amplifier performance?
    Slew rate is the maximum rate of change of the output voltage, typically measured in volts per microsecond (V/μs). It limits how quickly the output can respond to a sudden change in input. If the input signal changes faster than the slew rate allows, the output will become distorted, often turning a sine wave into a triangular wave. Slew rate is important in high-frequency, large-signal applications, such as audio power amplifiers and video amplifiers.
    How does negative feedback affect the performance of a real op-amp?
    Negative feedback reduces the closed-loop gain but improves many other performance characteristics: it increases bandwidth (by the same factor that gain is reduced), reduces distortion, stabilises the gain against variations in open-loop gain, and increases input impedance while decreasing output impedance. It also reduces the effect of offset voltage and bias current on the output, because the feedback forces the differential input voltage to be very small. Overall, negative feedback makes the circuit performance depend primarily on the external components rather than the op-amp itself.