Algebra - Notation, vocabulary and manipulation — Edexcel GCSE Mathematics
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Algebra - Notation, vocabulary and manipulation explained
Algebra has a shorthand, and questions expect you to read it and to write it.
Read the full explanation
The multiplication sign between letters is left out, so a × b is written ab, and the number goes in front of the letter, so 3 × y is written 3y. Repeated addition of the same letter collapses into a coefficient, so y + y + y is 3y. Repeated multiplication collapses into an index, so a × a is a², a × a × a is a³, and a × a × b is a²b. Division is written as a fraction, so a ÷ b becomes a/b. Coefficients are kept as fractions, so three quarters of x is written (3/4)x rather than 0.75x. Brackets show what an operation acts on: 2(x + 5) doubles the whole of x + 5, while 2x + 5 doubles only x.
substitute numerical values into formulae and expressions, including scientific formulae
Substitution means putting a given number in place of each letter, then working the expression out. Replace every copy of a letter, and keep the order of operations: brackets and indices first, then multiplication and division, then addition and subtraction. In v = u + at with u = 3, a = 4 and t = 5, the multiplication comes first, so at is 20 and v = 23. Write a negative value inside brackets before you use it. If x = −3, then 2x² means 2 × (−3)², which is 18, because the index acts on the x alone. Scientific formulae behave the same way: density = mass ÷ volume, so a mass of 240 g in a volume of 30 cm³ gives 8 g/cm³. Check which letter stands for which quantity before you start.
understand and use the concepts and vocabulary of expressions, equations, formulae, identities, inequalities, terms and factors
These words say what a piece of algebra is, and questions ask you to name them. An expression is a collection of terms with no equals sign, such as 3x + 5. A term is one part of an expression, separated from the next by a plus or a minus sign, so 3x + 5 has two terms. A factor is something that multiplies to give a quantity, so the factors of 6x include 2, 3, x and 6x. An equation has an equals sign and holds only for particular values, so 3x + 5 = 11 holds when x = 2. A formula is a rule linking quantities, such as area of a circle = πr². An identity holds for every value of the letter, and is written with the sign ≡ in place of an equals sign. An inequality, such as x > 4, is satisfied by a range of values.
simplify and manipulate algebraic expressions (including those involving surds) by: • collecting like terms • multiplying a single term over a bracket • taking out common factors • expanding products of two binomials • factorising quadratic expressions of the form x² + bx + c, including the difference of two squares; • simplifying expressions involving sums, products and powers, including the laws of indices (Foundation tier)
This is the toolkit for tidying algebra. Collect like terms by adding the coefficients of terms with exactly the same letters and powers, so 5a + 3b − 2a is 3a + 3b. Multiply a single term over a bracket by multiplying every term inside it, so 4(2x − 3) is 8x − 12. Take a common factor out by finding the largest factor of every term, so 6x + 9 is 3(2x + 3). Expand two brackets by multiplying each term in the first by each term in the second, so (x + 2)(x + 5) is x² + 7x + 10. To factorise x² + bx + c, find two numbers that multiply to c and add to b. The difference of two squares gives x² − 9 = (x + 3)(x − 3). For powers of the same base, multiplying adds the indices and dividing subtracts them, so x⁵ ÷ x² is x³. Surds simplify by taking out square factors, so √12 is 2√3.
simplify and manipulate algebraic expressions (including those involving surds and algebraic fractions) by: • collecting like terms • multiplying a single term over a bracket • taking out common factors • expanding products of two or more binomials • factorising quadratic expressions of the form x² + bx + c, including the difference of two squares; factorising quadratic expressions of the form ax² + bx + c • simplifying expressions involving sums, products and powers, including the laws of indices (Higher tier)
This is Higher tier only. On top of the shared toolkit it adds three things. Algebraic fractions: factorise the top and the bottom, then cancel a whole common bracket, so (x² − 9)/(x² + 7x + 12) simplifies to (x − 3)/(x + 4), valid when x is neither −3 nor −4. Products of more than two brackets: expand two of them first, write the quadratic down, then multiply it by the remaining bracket term by term. Quadratics of the form ax² + bx + c, where a is not 1: split the middle term into two numbers that multiply to ac and add to b. For 2x² + 7x + 3, ac is 6, and 6 and 1 fit, so write 2x² + 6x + x + 3, group it as 2x(x + 3) + 1(x + 3), and read off (2x + 1)(x + 3).
understand and use standard mathematical formulae; rearrange formulae to change the subject
A formula links quantities by a rule. Some formulae are standard and you are expected to recall them and use them as they stand, such as area of a circle = πr² and speed = distance ÷ time. Changing the subject means rewriting a formula so that a different letter stands alone on one side. Work backwards through the operations that were applied to that letter, doing the same thing to both sides each time. To make t the subject of v = u + at, subtract u from both sides to reach v − u = at, then divide both sides by a, giving t = (v − u)/a, which needs a to be non-zero. Undo a square root by squaring both sides, and undo a square by taking the square root, remembering that a positive number has a positive and a negative square root. If the new subject appears twice, gather those terms on one side, factorise it out, then divide by the bracket.
know the difference between an equation and an identity; argue mathematically to show algebraic expressions are equivalent, and use algebra to support and construct arguments (Foundation tier)
An equation holds for particular values of the letter; an identity holds for every value. So 3x + 6 = 12 is an equation, true only when x = 2, while 3(x + 2) ≡ 3x + 6 is an identity, true whatever x stands for. To show two expressions are equivalent, take one of them and expand and collect until it becomes the other, writing every step down. Trying a couple of numbers is not an argument on its own, because it says nothing about the values you did not try. Algebra also lets you argue about numbers in general. Write an even number as 2n, where n is a whole number, so an odd number is 2n + 1. Then (2n + 1) + (2n + 3) = 4n + 4 = 4(n + 1), which shows two consecutive odd numbers add to a multiple of 4.
know the difference between an equation and an identity; argue mathematically to show algebraic expressions are equivalent, and use algebra to support and construct arguments and proofs (Higher tier)
This is Higher tier only. It takes the shared content and adds proof: an argument in algebra that covers every case, not a check on a few numbers. Start by choosing letters that carry the conditions, so consecutive integers are n and n + 1, an even number is 2n and an odd number is 2n + 1, with n standing for any integer. Expand and simplify until the form you need appears, then say in words what it shows. For example, the difference between the squares of two consecutive integers is (n + 1)² − n², which simplifies to 2n + 1, and every number of that form is odd, so the difference is always odd. To disprove a statement you need one counter-example, given with the numbers that break it.
where appropriate, interpret simple expressions as functions with inputs and outputs. (Foundation tier)
A function is a rule that takes an input, does something to it, and gives one output. A simple expression can be read that way: 3x − 4 is the rule ‘multiply by 3, then subtract 4’, so an input of 5 gives an output of 11. A function machine draws the same rule as boxes in a row, read from left to right. To find an input from a known output, work backwards through the boxes and undo each operation, so an output of 20 needs 20 + 4 = 24, then 24 ÷ 3 = 8. One input always gives one output, though two inputs can share an output, as 3 and −3 both do for the rule x². Questions give you a machine with a blank box, or a table of inputs and outputs to complete.
where appropriate, interpret simple expressions as functions with inputs and outputs; interpret the reverse process as the ‘inverse function’; interpret the succession of two functions as a ‘composite function’ (the use of formal function notation is expected) (Higher tier)
This is Higher tier only. It adds formal notation to the idea of inputs and outputs. The rule is written f(x), so if f(x) = 3x − 4 then f(5) = 11. A composite applies two rules in succession: fg(x) means work out g(x) first, then put that result into f. With f(x) = 3x − 4 and g(x) = x + 2, fg(x) = 3(x + 2) − 4, which is 3x + 2, while gf(x) = 3x − 2, so the order changes the answer. The inverse f⁻¹(x) undoes f. To find it, write y = 3x − 4, rearrange to make x the subject, then swap the letters, which gives f⁻¹(x) = (x + 4)/3. A question may ask for a single value, such as fg(2), or for the whole expression.
Your focus
- Write down the shorthand for a × b, y + y + y and a × a × b, with no multiplication sign and the number in front.
- Interpret shorthand such as a²b or a/b by writing out what it stands for, keeping a fractional coefficient as a fraction.
- Explain the difference between 2(x + 5) and 2x + 5, and place brackets so the operation acts on the whole expression.
Show all 33 objectives
- Explain why a negative value is bracketed before substituting, so that 2x² with x = −3 gives 18 rather than −18.
- Calculate v from v = u + at with u = 3, a = 4 and t = 5, working out at before adding u.
- Use a scientific formula such as density = mass ÷ volume and give the answer with the unit that formula produces.
- Write down what an expression, an equation, a formula, an identity and an inequality each are.
- Use an equals sign in an equation and the sign ≡ in an identity, and list the terms and factors of a given expression.
- Explain why 3(x + 2) ≡ 3x + 6 is an identity while 3x + 5 = 11 is an equation, from the values each one holds for.
- Write down the rule for collecting like terms, that only terms with exactly the same letters and powers combine.
- Expand (x + 2)(x + 5) term by term, and factorise x² + bx + c by finding two numbers multiplying to c and adding to b.
- Factorise 6x + 9 as 3(2x + 3) by taking out the highest common factor, and check any factorisation by expanding it back.
- Factorise x² − 9 as a difference of two squares, and simplify x⁵ ÷ x² by subtracting the indices.
- Simplify an algebraic fraction by factorising numerator and denominator first, then cancelling a whole common bracket.
- Factorise 2x² + 7x + 3 by splitting the middle term into a pair that multiplies to ac and adds to b.
- Expand a product of three brackets by multiplying two of them first, then multiplying that quadratic term by term.
- Explain why a cancelled fraction excludes the values that made the original denominator zero, such as −3 and −4.
- Write down standard formulae such as area of a circle = πr² and speed = distance ÷ time before anything goes into them.
- Find t as the subject of v = u + at by subtracting u from both sides then dividing by a, which must be non-zero.
- Show that a new subject appearing in two terms can be isolated by gathering those terms, factorising it out and dividing.
- Explain the difference between an equation, true for particular values, and an identity, true for every value.
- Show that two expressions are equivalent by expanding and collecting one of them until it becomes the other.
- Explain why testing a few numbers proves nothing, and write an even number as 2n to argue about numbers in general.
- Write down letters that carry the condition, such as n and n + 1 for consecutive integers or 2n + 1 for an odd number.
- Show that the difference between the squares of two consecutive integers is 2n + 1 and therefore always odd.
- Prove a statement with a closing line linking the algebra back to the claim, or disprove it with one counter-example.
- Explain how 3x − 4 reads as the rule multiply by 3 then subtract 4, giving one output for each input.
- Work out the output of a function machine or expression from a given input, applying the operations in the order shown.
- Find an input from a known output by undoing each operation in reverse order, adding 4 before dividing by 3.
- Explain why 3 and −3 can share an output under the rule x² although one input never gives two outputs.
- Write down f(5) for f(x) = 3x − 4 using formal function notation rather than words.
- Work out fg(x) by substituting into the inner function g first, and show that fg(x) and gf(x) are different.
- Find f⁻¹(x) by writing y = 3x − 4, making x the subject and swapping the letters, then writing it in function notation.
Algebra - Notation, vocabulary and manipulation exam tips
Quick Revision Summary (Key Takeaway)
Algebraic notation, vocabulary and manipulation covers the core Edexcel GCSE skills of using letters to represent variables, simplifying expressions by collecting like terms, expanding brackets and factorising. Mastery of these techniques is essential because they underpin every other algebra topic, from solving equations to rearranging formulae and working with sequences.
Topic Overview
Algebraic notation, vocabulary and manipulation is a fundamental topic in GCSE Mathematics that introduces students to the language of algebra. It covers how to read and write algebraic expressions correctly, including the use of indices, coefficients, and terms, and how to simplify expressions by collecting like terms, expanding brackets, and factorising. This topic is essential because it provides the toolkit for solving equations, rearranging formulae, and understanding graphs and sequences.
In the Pearson Edexcel GCSE, this topic is assessed across both Foundation and Higher tiers, often as part of multi-step problems. Mastery of manipulation skills ensures students can access higher-mark questions in algebra, geometry, and problem-solving contexts. It also builds the foundation for more advanced topics such as quadratic expressions, algebraic fractions, and proof.
Key Concepts
- →Like terms: Terms with the same variable(s) raised to the same power can be combined by adding or subtracting their coefficients, e.g., 3x + 5x = 8x, but 3x + 5y cannot be simplified.
- →Expanding brackets: Multiply each term inside the bracket by the term outside, using the distributive law, e.g., a(b + c) = ab + ac. For double brackets, multiply each term in the first bracket by each term in the second.
- →Factorising: The reverse of expanding, where you write an expression as a product of its factors. Always take out the highest common factor (HCF) of all terms.
- →Indices laws: When multiplying powers of the same base, add the indices (a^m * a^n = a^(m+n)); when dividing, subtract them (a^m / a^n = a^(m-n)).
- →Substitution: Replacing variables with given numerical values and evaluating the expression using the correct order of operations (BIDMAS).
Marking Points
- writing the expression in correct shorthand, with no multiplication sign left in and the number placed in front of the letter
- showing what the shorthand stands for, such as writing a²b back out as a × a × b, even if the final line is wrong
- keeping a fractional coefficient as a fraction instead of rounding it to a decimal
- placing brackets so that the operation acts on the whole of the expression the question describes
- substituting the given values into every letter correctly, even if the arithmetic that follows is wrong
- evaluating in the correct order, with indices and brackets dealt with before multiplication
- the correct final value, carrying the units the scientific formula produces
- a value correctly carried forward into a later part after an earlier slip
- naming the object correctly, calling 3x + 5 an expression rather than an equation
- a reason that separates the two, such as saying an identity holds for all values while an equation holds only for some
- listing the terms or the factors the question asks for, with none left out
- choosing the right sign, an equals sign in an equation and the identity sign ≡ in an identity
- a correct expansion of each bracket before any collecting is done, even if the collecting then goes wrong
- collecting like terms accurately, keeping the sign that sits in front of each term
- taking out the highest common factor rather than a smaller factor of every term
- a correct pair of brackets, which an examiner checks by expanding it back to the original quadratic
- a correct index law applied to powers of the same base
- factorising the numerator and the denominator of an algebraic fraction before anything is cancelled
- cancelling a whole common bracket and writing the simplified fraction
- a correct product of the first two brackets, even if the final expansion is wrong
- splitting the middle term into a pair that multiplies to ac and adds to b
- the fully factorised quadratic written as two brackets
- writing down the correct standard formula before any values or any rearranging go into it
- a correct first step that isolates the term holding the new subject
- the same operation applied to both sides at each stage, even if the final rearrangement is wrong
- the new subject standing alone, with everything else on the other side
- factorising the new subject out when it appears in more than one term
- a correct expansion of the side you choose to work on, even if the two sides are never matched
- a general statement written in letters rather than a check on particular numbers
- reaching a form that displays the property asked for, such as a factorised multiple
- a closing line that states what has been shown
- correct use of the identity symbol ≡ where the statement is true for every value, and = where it is true only for particular values
- defining letters that express the condition, such as writing consecutive integers as n and n + 1
- correct expansion and simplification of the general expression
- reaching a form that demonstrates the claim, such as a factor of 2 or a bracket showing a multiple
- a concluding sentence that links the algebra back to the statement being proved
- a valid counter-example where the question asks you to disprove a statement
- applying the operations in the order the machine or the expression sets out
- a correct output from a given input, even if a later part of the question is wrong
- undoing the operations in reverse order to recover an input
- a table of inputs and outputs completed correctly throughout
- a correct inverse chain written down, such as ‘add 4, then divide by 3’ for 3x − 4
- substituting into the inner function first when a composite is worked out
- a correct unsimplified expression for fg(x) or gf(x), even if it is not tidied up
- a correct rearrangement when finding an inverse, even if the letters are not swapped at the end
- the inverse written in function notation rather than left as an equation in y
Examiner Tips
- 💡If the shorthand confuses you, write the multiplication out in full first, then collapse it back once you have the answer.
- 💡Keep a coefficient as a fraction all the way through; a decimal that does not terminate loses accuracy you cannot get back.
- 💡Before you write a bracket down, ask what the operation outside it is acting on, the first term or the whole expression.
- 💡Copy the formula out, then copy it again with the numbers in place, before you touch the calculator.
- 💡Put brackets round every negative number you type in, so the calculator applies the index to the sign as well.
- 💡If a question gives the rule in words, write it as a formula with letters first, then substitute.
- 💡If a statement stays true whatever you substitute, it is an identity; test two different values quickly to decide.
- 💡Count terms by the plus and minus signs between them, and keep the sign that sits in front of each one.
- 💡Read the command wording: naming a formula, solving an equation and proving an identity are three different jobs.
- 💡Expand your factorised answer back out in the margin; if it does not return the original expression, the factorising is wrong.
- 💡List the factor pairs of the constant term first, then test which pair adds to the middle coefficient.
- 💡Watch the sign in front of a bracket you are multiplying out; a negative outside changes the sign of every term inside.
- 💡Nothing cancels until the top and the bottom are each written as a product, so factorise both before you look for anything common.
- 💡With three brackets, do two at a time and write the intermediate quadratic down, so the method marks are visible.
- 💡Multiply your two brackets back out when the coefficient of x² is not 1; the middle term is where the error shows.
- 💡List the operations applied to the new subject in order, then undo them from the outside in.
- 💡Test your rearrangement by putting easy numbers into the original formula and into your version; both should agree.
- 💡When you divide, divide the whole of the other side, using a bracket to hold it together if you need one.
- 💡Work on one side only and drive it towards the other; do not move terms across the sign as though you were solving.
- 💡Define your letters before you use them, saying that n stands for any whole number.
- 💡Finish with a sentence that names the result, such as saying the expression is a multiple of 4.
- 💡State what each letter stands for, and say that it is an integer, before any manipulation.
- 💡Aim for a factorised form: 2 multiplied by an expression in n shows the result is even, and 3 multiplied by an expression in n shows a multiple of 3.
- 💡For a proof question, end with one sentence naming the property, since the final mark is usually for that conclusion.
- 💡Write the operations as a chain before you calculate, so the order is fixed on paper and not in your head.
- 💡Going backwards, reverse both the order and each operation, then feed your answer forwards to check it.
- 💡Fill in every cell of a table you are given; a value that breaks the pattern usually shows a slip.
- 💡For a numerical composite such as fg(2), work out g(2) as a number first, then feed that number into f.
- 💡Check an inverse by putting a value through f and then through f⁻¹; you should land back on the value you started with.
- 💡Write fg(x) and gf(x) out separately when a question compares them, because they are rarely the same expression.
- 💡Always show your working, especially when expanding and simplifying. Method marks are often available even if the final answer is wrong.
- 💡When factorising, always check your answer by expanding it back out. This helps you spot incomplete factorisation.
- 💡Pay close attention to signs, particularly when subtracting brackets or multiplying by negative numbers. Write out each step clearly to avoid careless errors.
Common Mistakes
- reading 3y as y × y × y, or reading a³ as a × 3
- writing 2a² when the question means (2a)², or squaring the coefficient when only the letter carries the index
- reversing a division, so writing a ÷ b as b/a
- dropping the bracket in 3(x + 4) and writing 3x + 4
- reading 3x with x = 4 as thirty-four rather than as 12
- squaring the coefficient as well as the letter, so evaluating 4x² at x = 3 as 12² rather than as 4 × 9
- losing the minus sign, so treating (−2)³ as 8 when it is −8
- mixing units, such as substituting a length in centimetres into a formula that expects metres
- calling any string of algebra an equation, even when there is no equals sign in it
- separating a term from the sign in front of it, so reading 5x − 2y as having a term 2y instead of −2y
- confusing factors with terms, so saying that the factors of 3x + 6 are 3x and 6
- calling a rule an equation when it links two quantities and is really a formula
- treating 3x and 3x² as like terms and adding their coefficients
- multiplying only the first term inside a bracket, so writing 4(2x − 3) as 8x − 3
- taking out a factor that is not the highest, leaving 2(3x + 6) where 6(x + 2) was wanted
- picking numbers that multiply to c but do not add to b, so writing x² + 5x + 6 as (x + 1)(x + 6)
- adding the indices when powers are added rather than multiplied
- cancelling a term rather than a factor, so turning (x + 6)/6 into x + 1
- expanding three brackets in one attempt and losing terms, instead of multiplying two of them first
- using factor pairs of c rather than of ac when the coefficient of x² is not 1
- writing (2x + 3)(x + 1) for 2x² + 7x + 3 without expanding to check the middle term
- adding algebraic fractions by adding the numerators and the denominators separately
- moving a term to the other side without changing its sign
- dividing only one term on a side, so turning v = u + at into v/a = u + t
- taking the square root of each term separately, so writing the square root of a² + b² as a + b
- stopping while the new subject is still multiplied by something, leaving an answer such as 2y = x
- testing two or three numbers and calling that a demonstration that the expressions are equivalent; a numerical check can suggest a result but cannot prove it for all values
- using one letter for two quantities that can differ, so making two consecutive numbers both n; use n and n + 1, or 2n + 1 and 2n + 3 for consecutive odd numbers
- treating an identity as an equation and solving it, ending with a line such as 0 = 0 and no conclusion; an identity is shown by expanding and collecting, not by solving
- stopping at 4n + 4 without factorising, so the multiple of 4 is never made visible; write 4(n + 1) to display the factor
- starting from the statement to be proved and working towards something true, rather than starting from the general case
- choosing letters that force a special case, such as using 2n and 2n + 1 for two consecutive integers, which makes the first one even
- expanding (n + 1)² as n² + 1 and losing the middle term
- giving several worked examples in place of a general argument
- stopping at the algebra without saying which property has been shown
- working a machine backwards in the same order as the forward operations; reverse the order as well as each operation
- reading 3x − 4 as subtract 4 first, so getting 3 from an input of 5; multiplication by 3 comes first
- using the wrong inverse, such as subtracting where the box multiplies; each operation is undone by its inverse
- forgetting that both 3 and −3 are inputs giving an output of 9 for the rule x²; one input gives one output, but two inputs may share an output
- reading fg(x) as f(x) multiplied by g(x)
- applying f before g in fg(x), so composing the two rules in the wrong order
- treating f⁻¹(x) as 1/f(x)
- rearranging correctly but leaving the answer in terms of y, so the inverse is never written as a function of x
- Misconception: 3a + 4b = 7ab. Correction: Only like terms can be combined. a and b are different variables, so 3a + 4b cannot be simplified further.
- Misconception: 5 - 2(x + 3) = 5 - 2x + 6. Correction: The negative sign applies to both terms inside the bracket: 5 - 2x - 6 = -2x - 1.
- Misconception: 2x * 3x = 6x. Correction: When multiplying terms, multiply coefficients and add indices: 2x * 3x = 6x^2.
Revision Plan
- 1Day 1-2: Revise key vocabulary and notation. Practice identifying like terms and simplifying expressions by collecting terms.
- 2Day 3-4: Master expanding single and double brackets. Work through examples with negative signs and coefficients.
- 3Day 5-6: Learn factorising techniques, including taking out common factors and factorising quadratic expressions (for Higher tier).
- 4Day 7-8: Practice mixed problems that combine expanding, simplifying, and factorising. Use past paper questions to test your skills.
- 5Day 9-10: Review common misconceptions and examiner tips. Complete a timed practice paper under exam conditions.
Exam Question Types
- 📋Simplify expressions by collecting like terms: Often appears as a short 1-2 mark question. Ensure you combine only like terms and write terms in alphabetical order.
- 📋Expand and simplify brackets: Typically a 2-3 mark question. Show each step of expansion and then collect like terms. Watch for negative signs.
- 📋Factorise expressions: Usually a 2-mark question. Always take out the highest common factor and check by expanding.
- 📋Solve equations involving algebraic manipulation: Multi-step problems where you must expand, simplify, and then solve. Show all steps clearly.
Command Word Expectations (PEARSON EDEXCEL)
Write the expression in its most compact form by collecting like terms and performing any indicated operations. No equals sign should be used unless it is an equation to solve.
Multiply out the brackets and simplify the resulting expression by collecting like terms. Show each multiplication step.
Write the expression as a product of factors. Take out the highest common factor of all terms. For quadratic expressions, factorise into two brackets.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: Expand and simplify 3(2x - 4) - 2(x - 5).
- 1.Step 1: Identify the expression and note the operations: multiply the first bracket by 3 and the second bracket by -2.
- 2.Step 2: Expand the first bracket: 3 * 2x = 6x and 3 * -4 = -12, giving 6x - 12.
- 3.Step 3: Expand the second bracket: -2 * x = -2x and -2 * -5 = +10, giving -2x + 10.
- 4.Step 4: Combine the results: 6x - 12 - 2x + 10.
- 5.Step 5: Collect like terms: 6x - 2x = 4x and -12 + 10 = -2, so the simplified expression is 4x - 2.
Question: Factorise fully 8x^2 - 12x.
- 1.Step 1: Identify the highest common factor (HCF) of the coefficients 8 and 12, which is 4.
- 2.Step 2: Identify the highest common power of x in both terms, which is x (since the lowest power is x^1).
- 3.Step 3: The overall HCF is 4x. Divide each term by 4x: 8x^2 / 4x = 2x and -12x / 4x = -3.
- 4.Step 4: Write the factorised expression as 4x(2x - 3).
- 5.Step 5: Check by expanding: 4x * 2x = 8x^2 and 4x * -3 = -12x, which matches the original expression.