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    Solving equations and inequalities — AQA GCSE Mathematics

    Verified courseTeaching note checked against the official specification.

    Solving equations and inequalities involves finding the unknown values that make a mathematical statement true, using inverse operations to isolate the variable. For inequalities, the solution is a range of values, and the inequality sign reverses when multiplying or dividing by a negative number.

    Solving equations and inequalities explained

    Solving equations and inequalities covers 10 specification points, including Solve linear equations in one unknown… and Including those with the unknown on both sides….

    Read the full explanation

    Open a point below for its explanation and revision guidance.

    solve linear equations in one unknown algebraically find approximate solutions using a graph

    This skill has two linked parts. Algebraically, you solve a linear equation in one unknown by using inverse operations to isolate the variable, keeping the equation balanced at every step. For example, to solve 3x + 5 = 20, subtract 5 from both sides to get 3x = 15, then divide both sides by 3 to get x = 5. Graphically, you can treat each side as a function, plot y = 3x + 5 and y = 20, and read the x-coordinate where the lines cross; that x-value is the approximate solution. The graph method is useful when an exact algebraic solution is difficult or when you need to check your answer. Both methods should give the same value, so you can use one to verify the other.

    including those with the unknown on both sides of the equation

    When the unknown appears on both sides of a linear equation, first collect the unknown terms on one side and the constant terms on the other. For example, to solve 5x + 2 = 3x + 10, subtract 3x from both sides to get 2x + 2 = 10, then subtract 2 from both sides to get 2x = 8, and finally divide by 2 to get x = 4. The same balance principle applies: whatever operation you perform on one side must be performed on the other. You can also solve such equations graphically by plotting each side as a straight line and reading the x-coordinate of their intersection. Always check your solution by substituting it back into the original equation.

    solve quadratic equations algebraically by factorising find approximate solutions using a graph

    A quadratic equation has an x² term. To solve algebraically by factorising, rearrange to the form ax² + bx + c = 0, then factorise into two brackets. For x² + 5x + 6 = 0, find two numbers that multiply to 6 and add to 5: 2 and 3, so (x + 2)(x + 3) = 0. Setting each bracket to zero gives x = -2 or x = -3. If the coefficient of x² is not 1, factor out common factors or use appropriate factor pairs. To find approximate solutions using a graph, plot or read the curve y = ax² + bx + c and identify where it crosses the x-axis; those x-intercepts are the approximate roots. For example, from a graph the curve may cross near x = -2.1 and x = 0.6, so solutions are approximately -2.1 and 0.6. Always check by substitution.

    including those that require rearrangement including completing the square and by using the quadratic formula (Higher tier only)

    Higher tier students solve quadratic equations that need rearrangement before solving. Rearrange to ax² + bx + c = 0, then choose a method. Completing the square writes x² + bx + c as (x + b/2)² - (b/2)² + c; for example, x² + 6x + 5 = 0 becomes (x + 3)² - 4 = 0, so (x + 3)² = 4, x + 3 = ±2, giving x = -1 or x = -5. The quadratic formula x = (-b ± √(b² - 4ac)) / (2a) solves any quadratic in standard form; for 2x² + 3x - 2 = 0, a = 2, b = 3, c = -2, so x = (-3 ± √(9 + 16)) / 4 = (-3 ± 5) / 4, giving x = 0.5 or x = -2. Both methods may produce surd solutions; leave them exact unless asked for decimals.

    solve two simultaneous equations in two variables (linear/linear) algebraically find approximate solutions using a graph

    This topic requires you to solve a pair of linear simultaneous equations in two variables algebraically, and to use a graph to find approximate solutions. Algebraically, use elimination or substitution. For example, to solve 2x + y = 7 and x − y = 2, adding the equations eliminates y, giving 3x = 9, so x = 3; substituting back gives y = 1. Graphically, draw both straight lines on the same axes; the point where they cross gives the approximate solution. You should be able to read off coordinates from a graph, recognising that the intersection may not be exact. The algebraic method gives an exact answer, while the graph gives an approximate answer. Always check your solution by substituting back into both original equations.

    including linear/quadratic (Higher tier only)

    At Higher tier, you must solve simultaneous equations where one is linear and the other is quadratic. The standard method is substitution: rearrange the linear equation to make one variable the subject, then substitute this expression into the quadratic equation. This produces a quadratic equation in one variable, which you solve by factorising, completing the square or using the quadratic formula. Each solution for one variable is then substituted back into the linear equation to find the corresponding value of the other variable. Because a quadratic can have two, one or no real solutions, there may be two, one or no pairs of solutions. Present your final answers as coordinate pairs and check them in both original equations.

    find approximate solutions to equations numerically using iteration (Higher tier only)

    Iteration finds approximate solutions to equations that cannot be solved exactly. Rearrange the equation into the form x = g(x), choose a starting value x₀, and repeatedly apply the formula xₙ₊₁ = g(xₙ). Each result is substituted back until successive values settle to a required accuracy. For example, to solve x³ + x = 20, rearrange to x = ∛(20 − x). Starting at x₀ = 2 gives x₁ = ∛18 ≈ 2.6207, x₂ ≈ 2.5903, x₃ ≈ 2.5918, converging near 2.592. A good starting value and a convergent rearrangement are essential, as some rearrangements diverge. You must show enough iterations to justify the accuracy of your answer and interpret the result in context.

    translate simple situations or procedures into algebraic expressions or formulae derive an equation (or two simultaneous equations), solve the equation(s) and interpret the solution

    This skill links algebra to real situations. You define a variable for the unknown quantity, translate the words into an expression or formula, then form an equation or a pair of simultaneous equations. For example, if a rectangle has length 3 cm more than its width w, its perimeter is 2(w + w + 3) = 4w + 6. If the perimeter is 26 cm, solve 4w + 6 = 26 to get w = 5, so the width is 5 cm and the length is 8 cm. For two unknowns, such as the cost of adult and child tickets, form two equations and solve them by elimination or substitution. Always check the solution in the original context and state what it represents, including units where appropriate.

    solve linear inequalities in one variable represent the solution set on a number line

    A linear inequality in one variable compares expressions using <, >, ≤ or ≥. To solve it, rearrange similarly to a linear equation: collect variable terms on one side and constants on the other, then divide by the coefficient. Crucially, multiplying or dividing both sides by a negative number reverses the inequality sign. For example, solving 3x + 2 < 11 gives 3x < 9, so x < 3. Solving 5 − 2x ≥ 1 gives −2x ≥ −4, so x ≤ 2. The solution set is then represented on a number line: use an open circle for a strict inequality (<, >) and a filled circle for inclusive inequalities (≤, ≥). Draw an arrow or line from the circle indicating all values in the direction of the solution.

    solve linear inequalities in one or two variable(s), and quadratic inequalities in one variable represent the solution set on a number line, using set notation and on a graph (Higher tier only)

    At Higher tier, inequalities extend to linear inequalities in one or two variables and quadratic inequalities in one variable. A linear inequality in two variables, such as y < 2x + 1, is solved by rearranging to make y the subject and then representing the solution set as a region on a graph, using a dashed boundary line for strict inequalities and a solid line for ≤ or ≥. A quadratic inequality in one variable, such as x² − 5x + 6 < 0, is solved by finding the critical values where the quadratic equals zero, then testing intervals to determine where the inequality holds. The solution set can be shown on a number line, in set notation such as {x : 2 < x < 3}, and on a graph.

    Your focus

    1. Solve a linear equation in one unknown algebraically by using inverse operations.
    2. Find an approximate solution to a linear equation by reading the x-coordinate of the intersection of two graphs.
    3. Verify an algebraic solution by substitution or by comparing it with a graphical solution.
    Show all 30 objectives
    1. Solve linear equations with the unknown on both sides by collecting like terms and using inverse operations.
    2. Check solutions to equations with unknowns on both sides by substitution.
    3. Find approximate solutions to such equations by reading the x-coordinate of the intersection of two graphs.
    4. Rearrange a quadratic equation into the form ax² + bx + c = 0.
    5. Factorise a quadratic expression and use the zero product property to find exact solutions.
    6. Interpret the x-intercepts of a quadratic graph to estimate solutions.
    7. Rearrange a quadratic equation into standard form before solving.
    8. Solve quadratic equations by completing the square.
    9. Apply the quadratic formula accurately to find solutions.
    10. Solve a pair of linear simultaneous equations algebraically using elimination or substitution.
    11. Find approximate solutions to simultaneous equations by reading the intersection point from a graph.
    12. Verify solutions by substitution into the original equations.
    13. Solve simultaneous equations where one equation is linear and the other is quadratic using substitution.
    14. Solve the resulting quadratic equation to find all possible values of one variable.
    15. Find the corresponding values of the other variable and present all solution pairs.
    16. Rearrange a given equation into the form x = g(x) suitable for iteration.
    17. Carry out an iterative process accurately using a calculator and record successive approximations.
    18. Determine an approximate solution to a required degree of accuracy and recognise non-convergent iterations.
    19. Translate a simple situation or procedure into an algebraic expression or formula.
    20. Derive and solve a linear equation or a pair of simultaneous equations from a given context.
    21. Interpret the solution in terms of the original situation, including units and checks.
    22. Solve a linear inequality in one variable by rearranging and, where necessary, reversing the inequality sign.
    23. Represent the solution set of a linear inequality on a number line using open or filled circles and the correct direction.
    24. Check a solution set by substituting a value from the set into the original inequality.
    25. Solve linear inequalities in one or two variables and quadratic inequalities in one variable.
    26. Represent solution sets on a number line, using set notation and on a graph with correct boundary line styles.
    27. Determine the correct region for a quadratic inequality by testing intervals between critical values.

    Which command word is this?

    Find the value(s) of the variable that make the equation or inequality true. Show all steps of your working. For inequalities, state the solution set and represent it if asked.

    Solving equations and inequalities exam tips

    Topic Overview

    Solving equations and inequalities is a fundamental algebra topic in GCSE Mathematics. It involves finding the value(s) of an unknown variable that satisfy a given equation or inequality. Equations use the equals sign (=) and typically have one or more specific solutions, while inequalities use symbols like <, >, ≤, ≥ and have a range of solutions. Mastery of this topic is essential for higher-level algebra, problem-solving, and many real-world applications.

    This topic builds on basic arithmetic and algebraic manipulation, extending to linear, quadratic, and simultaneous equations. It appears across all exam boards, including AQA GCSE, and is a prerequisite for topics such as graphs, sequences, and calculus. A strong understanding of inverse operations, balancing, and the rules for inequalities is crucial for success in both foundation and higher tier exams.

    Key Concepts
    • →Equations must be balanced: whatever operation you perform on one side, you must do to the other.
    • →Use inverse operations to isolate the variable: for example, if 3x + 2 = 11, subtract 2 then divide by 3.
    • →Inequalities are solved similarly to equations, but the inequality sign reverses when multiplying or dividing by a negative number.
    • →For quadratic equations, factorise, complete the square, or use the quadratic formula to find solutions.
    • →Simultaneous equations can be solved by elimination or substitution, finding values that satisfy both equations.
    Marking Points
    • Use inverse operations that preserve equality to isolate the unknown, performing the same operation on both sides.
    • Check the algebraic solution by substituting it back into the original equation.
    • For a graphical method, plot each side of the equation as a separate straight-line graph on the same axes.
    • Read the x-coordinate of the point of intersection to obtain the approximate solution.
    • Recognise that the graphical solution may be approximate because it depends on reading accuracy.
    • Collect the unknown terms on one side of the equation by adding or subtracting the same term from both sides.
    • Collect the constant terms on the other side by adding or subtracting the same number from both sides.
    • Divide or multiply both sides by the coefficient of the unknown to isolate it.
    • Check the solution by substituting it back into the original equation and confirming both sides are equal.
    • For a graphical approach, plot each side as a straight line and read the x-coordinate of the intersection point.
    • Rearranges a quadratic equation into the standard form ax² + bx + c = 0 before factorising.
    • Factorises a quadratic expression correctly, including cases where a common factor is taken out first.
    • Uses the zero product property: if (x + p)(x + q) = 0 then x = -p or x = -q.
    • Solves quadratic equations where the coefficient of x² is greater than 1 by factorising.
    • Reads approximate solutions from the x-intercepts of the graph of y = ax² + bx + c.
    • Checks algebraic solutions by substituting back into the original equation.
    • Rearranges a quadratic equation into the form ax² + bx + c = 0 before completing the square or using the quadratic formula.
    • Completes the square correctly, including when the coefficient of x² is not 1, by factoring out that coefficient first.
    • Solves the equation obtained after completing the square, remembering both the positive and negative square roots.
    • Substitutes the correct values of a, b and c into the quadratic formula, including negative signs.
    • Simplifies the resulting expression, leaving surd answers in exact form where required.
    • Correctly eliminate one variable by adding or subtracting the equations, or by substitution, to form a single equation in one variable.
    • Solve the resulting linear equation accurately to find the value of one variable.
    • Substitute the found value back into one of the original equations to find the other variable.
    • State the solution as a coordinate pair (x, y) and verify by substitution into both original equations.
    • For graphical solutions, plot both lines accurately and read the coordinates of the intersection point, giving an approximate answer.
    • Rearrange the linear equation to express one variable in terms of the other.
    • Substitute this expression into the quadratic equation to obtain a quadratic equation in one variable.
    • Solve the quadratic equation correctly, finding both solutions where they exist.
    • Substitute each value back into the linear equation to find the corresponding value of the other variable.
    • State all solution pairs clearly as coordinates and verify by substitution into both original equations.
    • Rearranges the given equation correctly into the iterative form x = g(x), for example x = ∛(20 − x) from x³ + x = 20.
    • Uses a sensible starting value x₀ and substitutes it correctly into the iteration formula to obtain x₁.
    • Repeats the iteration accurately, showing successive values, until two consecutive values agree to the required degree of accuracy.
    • States the approximate solution to the required accuracy, for example x ≈ 2.59 to 2 decimal places, and shows sufficient iterations to justify it.
    • Recognises when an iteration diverges or oscillates and adjusts the rearrangement or starting value accordingly.
    • Defines a variable clearly, for example let w be the width in centimetres, and uses it consistently.
    • Translates the situation correctly into an algebraic expression or formula, such as 4w + 6 for the perimeter.
    • Forms a correct equation or a correct pair of simultaneous equations from the given information.
    • Solves the equation or simultaneous equations accurately using an appropriate method, showing sufficient working.
    • Interprets the solution in the context of the problem, stating the values of the unknowns with correct units and checking against the original conditions.
    • Rearranges the inequality correctly by adding or subtracting the same quantity from both sides.
    • Divides or multiplies both sides by the coefficient of the variable, reversing the inequality sign when the multiplier or divisor is negative.
    • States the solution set correctly, for example x < 3 or x ≤ 2.
    • Draws a number line with an open circle for < or > and a filled circle for ≤ or ≥.
    • Indicates the correct direction of the solution set with an arrow or line extending from the circle.
    • Solves a linear inequality in one or two variables by rearranging correctly and, where necessary, reversing the inequality sign when multiplying or dividing by a negative number.
    • Finds the critical values of a quadratic inequality by solving the associated quadratic equation.
    • Tests intervals between and beyond the critical values to determine where the quadratic inequality is satisfied.
    • Represents the solution set on a number line with correct open or filled circles and direction.
    • Uses set notation correctly, for example {x : 2 < x < 3} or {x : x ≤ −1} ∪ {x : x ≥ 4}.
    • Draws the boundary line correctly on a graph, using a dashed line for strict inequalities and a solid line for inclusive inequalities, and shades the correct region.
    Examiner Tips
    • 💡Show each algebraic step clearly so that method marks can be awarded even if the final answer is wrong.
    • 💡When using a graph, draw the lines accurately and label the intersection point before reading the x-value.
    • 💡Substitute your solution back into the original equation to confirm it works, especially in multiple-choice questions where options may be close.
    • 💡Write down each step of your rearrangement so that method marks can be awarded even if the final answer is incorrect.
    • 💡After solving, substitute your value back into the original equation to check both sides are equal.
    • 💡In multiple-choice questions, substitute each option into the equation to see which one works, especially if you are unsure of your algebraic method.
    • 💡Always rearrange the equation to the form ax² + bx + c = 0 before factorising, and show this step clearly.
    • 💡When using a graph, state that you are reading the x-axis intercepts and give your answers to a suitable degree of accuracy, such as one decimal place.
    • 💡Check each solution by substituting it back into the original equation; this catches sign errors quickly.
    • 💡If a question asks for solutions in surd form, leave the answer with a square root and simplify it fully; do not round to a decimal.
    • 💡When using the quadratic formula, write down the values of a, b and c before substituting to reduce sign errors.
    • 💡After completing the square, show the step where you take the square root of both sides, including the ± sign, to secure method marks.
    • 💡Show your working clearly, especially the elimination or substitution steps, as method marks may be available.
    • 💡When using a graph, draw the lines with a ruler and label them; read the intersection carefully and state that it is approximate.
    • 💡Always check your solution by substituting back into both original equations; this can catch arithmetic errors.
    • 💡Write down the substitution step clearly so that the examiner can follow your method.
    • 💡If the quadratic does not factorise easily, use the quadratic formula and leave answers in surd form if required, unless told to round.
    • 💡Always check each solution pair in both original equations to ensure they satisfy both.
    • 💡Always write down your rearrangement and starting value before iterating, so the method is clear.
    • 💡Show at least three or four iterations in a table, keeping full calculator display values until the final rounding.
    • 💡Check convergence by comparing consecutive values; if they are not settling, reconsider your rearrangement.
    • 💡Write a clear 'let' statement defining each variable before forming any equation.
    • 💡Show each stage of forming and solving the equation so method marks can be awarded even if an arithmetic slip occurs.
    • 💡Substitute your solution back into the original word problem to check it satisfies all conditions.
    • 💡Finish with a sentence interpreting the answer in context, including units.
    • 💡Always check whether the coefficient of the variable is negative before dividing, because this determines whether the inequality sign reverses.
    • 💡Substitute a test value from your solution set back into the original inequality to confirm the direction is correct.
    • 💡Label the number line clearly and use the correct circle type: open for strict inequalities and filled for inclusive inequalities.
    • 💡For quadratic inequalities, always find the critical values first and then test a value in each interval to confirm the solution set.
    • 💡When drawing a graph, label the boundary line clearly and use the correct line style for strict or inclusive inequalities.
    • 💡Write the solution set in more than one form where possible, such as on a number line and in set notation, to show full understanding.
    • 💡Check whether the inequality is strict or inclusive before deciding on open or filled circles and dashed or solid lines.
    • 💡Always show your working, even for simple equations. Method marks are awarded for correct steps, so you can still gain marks even if the final answer is wrong.
    • 💡For inequalities, represent the solution on a number line as requested. Use an open circle for < or > and a closed circle for ≤ or ≥.
    • 💡Check your solution by substituting it back into the original equation or inequality. This helps catch errors and confirms your answer is correct.
    Common Mistakes
    • Applying an operation to only one side of the equation; correct this by always performing the same operation to both sides.
    • Dividing only the unknown term rather than every term on both sides. If you divide first, divide each complete side by the same non-zero number; subtracting the constant first is often simpler.
    • Reading the y-coordinate of the intersection point instead of the x-coordinate; correct this by identifying that the solution is the x-value where the two graphs meet.
    • Assuming a graph always gives an exact answer; correct this by stating that graphical solutions are approximate and should be checked algebraically where possible.
    • Moving a term without changing its sign; correct this by remembering that adding or subtracting a term from both sides reverses its sign on the side it is moved from.
    • Collecting unknowns on the side that makes the coefficient negative; correct this by choosing to collect on the side that keeps the coefficient positive where possible, or by carefully handling negative coefficients.
    • Forgetting to divide the constant term by the coefficient; correct this by dividing every term by the coefficient of the unknown.
    • Reading the y-coordinate of the intersection point on a graph instead of the x-coordinate; correct this by identifying that the solution is the x-value where the two lines cross.
    • Forgetting to rearrange to = 0 before factorising; for example, solving x² + 5x = -6 by writing (x + 2)(x + 3) = -6 and then incorrectly setting each bracket to -6. Correction: first add 6 to both sides to get x² + 5x + 6 = 0, then factorise and set each bracket to 0.
    • Sign errors when finding the roots from brackets; for example, from (x + 2)(x + 3) = 0 writing x = 2 or x = 3. Correction: solve x + 2 = 0 to get x = -2 and x + 3 = 0 to get x = -3.
    • Reading the y-intercept instead of the x-intercepts from a graph. Correction: approximate solutions are the x-values where the curve crosses the x-axis, not where it crosses the y-axis.
    • Forgetting to rearrange to = 0 before using the quadratic formula; for example, using the formula on x² + 3x = 4 without first writing x² + 3x - 4 = 0. Correction: always rearrange to ax² + bx + c = 0 and identify a, b and c from that form.
    • Sign errors when substituting negative values into the quadratic formula; for example, taking b = -3 when b is actually 3, or mishandling -b. Correction: write down a, b and c clearly, then substitute carefully, using brackets for negative numbers.
    • When completing the square, forgetting to subtract (b/2)² after adding it, or losing the constant term. Correction: check the expansion of your completed-square form to confirm it matches the original expression.
    • Forgetting to multiply both sides of an equation when using elimination, leading to an incorrect elimination step. Correction: always apply the same operation to the entire equation.
    • Substituting the found value into the wrong equation or making an arithmetic error. Correction: substitute into the simpler equation and check in both.
    • Reading the intersection point from a graph inaccurately, for example misreading the scale. Correction: use a ruler and check that the point lies on both lines.
    • Giving the solution as two separate numbers without indicating which is x and which is y. Correction: always write the answer as a coordinate pair (x, y).
    • Substituting into the quadratic without rearranging the linear equation correctly, leading to an equation that is not quadratic. Correction: always rearrange first and check the substitution.
    • Losing one of the solutions by dividing by a variable or by not considering both roots. Correction: solve the quadratic fully, using factorisation or the formula, and list both roots.
    • Forgetting to find the corresponding values of the other variable for each root. Correction: always substitute each root back into the linear equation.
    • Making sign errors when expanding brackets after substitution. Correction: expand carefully and check each term.
    • Substituting into the original equation instead of the rearranged iterative formula; the correction is to apply xₙ₊₁ = g(xₙ) at each step.
    • Rounding intermediate values too early, which prevents convergence; the correction is to keep full calculator accuracy and round only the final answer.
    • Assuming any rearrangement will converge; the correction is to test the iteration and, if values diverge, choose a different rearrangement or starting value.
    • Stopping after one or two iterations without evidence of convergence; the correction is to continue until successive values agree to the required accuracy.
    • Failing to define the variable or using different letters for the same unknown; the correction is to state clearly what each letter represents and use it throughout.
    • Forming an equation from only part of the information, such as using the perimeter formula without the length relationship; the correction is to include every given condition.
    • Solving correctly but not returning to the context, leaving the answer as a bare number; the correction is to state what the value means, for example the width is 5 cm.
    • Making sign errors when solving simultaneous equations by elimination; the correction is to check by substituting both values back into both original equations.
    • Forgetting to reverse the inequality sign when multiplying or dividing by a negative number; the correction is to reverse the sign whenever the multiplier or divisor is negative.
    • Using a filled circle for a strict inequality such as x < 3; the correction is to use an open circle for strict inequalities and a filled circle only for ≤ or ≥.
    • Drawing the arrow in the wrong direction after solving, for example showing x > 3 when the solution is x < 3; the correction is to check the final inequality before drawing the arrow.
    • Treating the inequality as an equation and giving a single value rather than a solution set; the correction is to state the range of values and show it on the number line.
    • Assuming a quadratic inequality is satisfied between the critical values without testing; the correction is to test a value in each interval to determine the correct region.
    • Using a solid boundary line for a strict inequality on a graph; the correction is to use a dashed line for < and > and a solid line for ≤ and ≥.
    • Writing set notation incorrectly, such as omitting the variable or using the wrong inequality signs; the correction is to write the set clearly, for example {x : x > 2}.
    • Forgetting to reverse the inequality sign when dividing by a negative number in a two-variable inequality; the correction is to reverse the sign whenever the multiplier or divisor is negative.
    • Students often forget to reverse the inequality sign when multiplying or dividing by a negative number. For example, solving -2x > 6 should give x < -3, not x > -3.
    • When solving equations with fractions, students may multiply only one term by the denominator instead of every term. Always multiply the entire equation by the common denominator.
    • Students sometimes assume that all equations have integer solutions. Solutions can be fractions, decimals, or surds, and should be left in exact form unless told otherwise.
    Revision Plan
    1. 1Day 1-2: Revise solving linear equations, including those with brackets and fractions. Practice at least 10 equations of increasing difficulty.
    2. 2Day 3-4: Learn and practice solving linear inequalities, focusing on the rule for reversing the sign. Represent solutions on number lines.
    3. 3Day 5-6: Tackle quadratic equations by factorising, completing the square, and using the formula. Practice identifying the most efficient method.
    4. 4Day 7-8: Master simultaneous equations using elimination and substitution. Solve problems involving both linear and quadratic equations.
    5. 5Day 9-10: Complete mixed exam-style questions under timed conditions. Review mistakes and revisit weak areas.
    Exam Question Types
    • 📋Solve a linear equation: often presented as a straightforward equation like 4x - 7 = 21. Show each step clearly to secure method marks.
    • 📋Solve an inequality and represent on a number line: e.g., solve 3 - 2x < 9 and draw the solution. Remember to reverse the sign when dividing by a negative.
    • 📋Solve simultaneous equations: typically two linear equations, but higher tier may include one linear and one quadratic. Use elimination or substitution and check your answer.
    • 📋Form and solve an equation from a word problem: e.g., 'The perimeter of a rectangle is 30 cm. Its length is 3 cm more than its width. Find the dimensions.' Define variables, set up an equation, solve, and interpret the solution.
    Command Word Expectations (AQA)
    Solve

    Find the value(s) of the variable that make the equation or inequality true. Show all steps of your working. For inequalities, state the solution set and represent it if asked.

    Show that

    Prove a given result by logical steps. You must show every stage of your working, often leading to a specific equation or value. No marks for just stating the result.

    Represent

    Draw a diagram, such as a number line, to show the solution set of an inequality. Use correct notation: open or closed circles and arrows.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Forgetting to reverse the inequality sign when multiplying or dividing by a negative number, leading to an incorrect solution set.
    ❌ Weak Answer (Loses Marks):Solve -2x > 8, so x > -4.
    Example improved answer:Solve -2x > 8. Divide both sides by -2 and reverse the inequality sign: x < -4.
    Examiner Tip: Always check if you multiply or divide by a negative number. If you do, flip the inequality sign immediately. A quick test with a number can verify your answer.
    Pitfall: Losing marks by not showing all steps when solving equations, especially when expanding brackets or dealing with fractions.
    ❌ Weak Answer (Loses Marks):3(x + 2) = 15, so x = 3.
    Example improved answer:3(x + 2) = 15. Expand: 3x + 6 = 15. Subtract 6: 3x = 9. Divide by 3: x = 3.
    Examiner Tip: Write every step clearly. Even if you can do it mentally, show the expansion, rearrangement, and division. This secures method marks and helps you spot errors.
    Step-by-Step Worked Solutions

    Question: Solve the inequality 5 - 3x ≤ 14 and represent the solution on a number line.

    1. 1.Step 1: Subtract 5 from both sides: -3x ≤ 9.
    2. 2.Step 2: Divide both sides by -3 and reverse the inequality sign: x ≥ -3.
    3. 3.Step 3: Draw a number line with a closed circle at -3 and an arrow pointing to the right.
    Final Answer: x ≥ -3, shown with a closed circle at -3 and arrow to the right.

    Question: Solve the simultaneous equations: 2x + y = 11 and 3x - y = 4.

    1. 1.Step 1: Add the two equations to eliminate y: (2x + y) + (3x - y) = 11 + 4, giving 5x = 15.
    2. 2.Step 2: Solve for x: x = 3.
    3. 3.Step 3: Substitute x = 3 into 2x + y = 11: 6 + y = 11, so y = 5.
    4. 4.Step 4: Check in second equation: 3(3) - 5 = 4, correct.
    Final Answer: x = 3, y = 5.
    Active Recall Memory Test
    What happens to the inequality sign when you multiply or divide both sides by a negative number?
    Key Fact: The inequality sign reverses direction. For example, if -2x > 6, then x < -3.
    How do you solve an equation with fractions, such as x/3 + x/4 = 7?
    Key Fact: Multiply every term by the common denominator (12) to eliminate fractions: 4x + 3x = 84, so 7x = 84, x = 12.
    What are the two main methods for solving simultaneous equations?
    Key Fact: Elimination (adding or subtracting equations to eliminate one variable) and substitution (expressing one variable in terms of the other and substituting).
    How do you represent x > 2 on a number line?
    Key Fact: Draw an open circle at 2 and an arrow pointing to the right, indicating all numbers greater than 2.
    Frequently Asked Questions
    How do I solve an equation with brackets?
    First, expand the brackets by multiplying each term inside by the number outside. Then collect like terms and use inverse operations to isolate the variable. For example, 3(x + 4) = 21 becomes 3x + 12 = 21, then 3x = 9, so x = 3. Always check your answer by substituting back into the original equation.
    When do I flip the inequality sign?
    You flip the inequality sign when you multiply or divide both sides of the inequality by a negative number. For example, solving -3x < 12 requires dividing by -3, giving x > -4. Adding or subtracting a negative number does not flip the sign. Always double-check if you have performed a multiplication or division by a negative.
    What is the difference between an equation and an inequality?
    An equation states that two expressions are equal, using the = sign, and typically has specific solution(s). An inequality states that one expression is greater than, less than, greater than or equal to, or less than or equal to another, using symbols like <, >, ≤, ≥, and has a range of solutions. For example, x + 2 = 5 has solution x = 3, while x + 2 > 5 has solution x > 3.
    How do I solve simultaneous equations by elimination?
    To solve by elimination, manipulate the equations so that the coefficients of one variable are the same (or opposites). Then add or subtract the equations to eliminate that variable. Solve for the remaining variable, then substitute back to find the other. For example, with 2x + y = 7 and 3x - y = 8, adding gives 5x = 15, so x = 3, then y = 1.
    Can I use the quadratic formula for any quadratic equation?
    Yes, the quadratic formula x = [-b ± √(b² - 4ac)] / 2a can solve any quadratic equation of the form ax² + bx + c = 0. However, it is often quicker to factorise if the factors are obvious. The formula is especially useful when factorising is difficult or impossible with integers. Remember to check the discriminant b² - 4ac to determine the number of solutions.
    How do I check if my solution to an equation is correct?
    Substitute your solution back into the original equation and evaluate both sides. If the left-hand side equals the right-hand side, your solution is correct. For inequalities, pick a value within your solution range and test it. This step is crucial to catch arithmetic errors and ensure you have not made a mistake in rearranging.